Answer:
6.61 L
Explanation:
M1 = 6.25
V1 = 15.58
M2 = 14.73
M1V1 = M2V2
(6.25)(15.58) = (14.73)V2
V2 = 6.61 L
No of molecules=26.02×10²³molecules
No of moles
- 26.02×10²³/6.023×10²³
- 4.3mol
Molar mass
- C2H8
- 2(12)+8(1)
- 24+8
- 32g/mol
Mass
- Moles×Molar mass
- 32(4.3)
- 137.6g
Answer:
See explanation below
Explanation:
To solve this problem, we need to use the expression of half life decay of concentration (or mass) which is the following:
m = m₀e^-kt (1)
In this case, k will be the constant rate of this element. This is calculated using the following expression:
k = ln2/t₁/₂ (2)
Let's calculate the value of k first:
k = ln2/2.7 = 0.2567 d⁻¹
Now, we can use the expression (1) to calculate the remaining mass:
m = 8.1 * e^(-0.2567 * 2.6)
m = 8.1 * e^(-0.6674)
m = 8.1 * 0.51303
m = 4.16 mg remaining