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Korolek [52]
3 years ago
9

A scuba diver with a local Sheriff’s office has been assigned the task of retrieving a sunken vessel in the Ocean. The vessel is

believed to have human remains inside. The scuba diver descends to a depth that is 60 feet below the surface of the ocean and breathes out a stream of bubbles. What is the total gas pressure of these bubbles at the moment they are released? What is the gas pressure in the bubbles when they reach the surface of the river?
Chemistry
1 answer:
n200080 [17]3 years ago
4 0
First, we convert the depth of the water into meters. This is:
60 feet = 18.3 meters

Now, we compute the additional pressure exerted due to the water, which is given by:
Pressure = density * gravitational field strength * height
P = 1000 * 9.81 * 18.3
P = 179.5 kPa

The atmosphere pressure is 101.325 kPa
The pressure of the gas bubbles 60 feet under water will be:
179.5 + 101.325 = 280.825 kPa

The pressure at the surface of the water will be equal to the atmospheric pressure, 101.325 kPa.

Because of this decrease in external pressure as gas bubbles rise, they are seen to expand.
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<u>Answer:</u> The partial pressure of gas number 3 is 159 mmHg

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Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of gas number 3, we use the law given by Dalton, which is:

P_T=p_{1}+p_{2}+p_3

We are given:

Total pressure of the tank, P_T = 950 mmHg

Vapor pressure of gas number 1, p_{1} = 335 mmHg

Vapor pressure of gas number 2, p_{2} = 456 mmHg

Putting values in above equation, we get:

950=335+456+p_3\\\\p_{3}=[950-(335+456)]=159mmHg

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Answer:

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