Question

Kramer goes bowling and decides to employ the force of gravity to "pick up a spare." He rolls the 8.00 kg8.00 kg bowling ball very slowly so that it comes to rest a center-to-center distance of 0.200 m0.200 m from the one remaining 2.75 kg2.75 kg bowling pin. Treat both the ball and the pin as point objects, and determine the magnitude of the force of gravity ????⃗ gravF→grav between them.

Answer 1

Answer:

$F = 3.6\times 10^{-8} N$

Explanation:

Given data:

mas of bowling ball 8.00 kg

centre to centre distance is 0.200 m

second mass of bowling 2.75 kg

we know that

$F = \frac{GmM}{D^2}$

Where is G is gravitational constant $= 6.674\times 10^{-11}$

$F = \frac{6.674\times 10^{11} \times 8 \times 2.5}{0.2^2}$

$F = 3.6\times 10^{-8} N$