Answer:
The final velocity of the car A is -1.053 m/s.
Explanation:
For an elastic collision both the kinetic energy and the momentum of the system are conserved.
Let us call
= mass of car A;
= the initial velocity of car A;
= the final velocity of car A;
and
= mass of car B;
= the initial velocity of car B;
= the final velocity of car B.
Then, the law of conservation of momentum demands that

And the conservation of kinetic energy says that

These two equations are solved for final velocities
and
to give


by putting in the numerical values of the variables we get


and


Thus, the final velocity of the car A is -1.053 m/s and of car B is 3.49 m/s.
Answer:
The correct option is D
Explanation:
In the course of the experiment, two key phrases/variables defined the experiment done,
i) the release height of the steel ball (independent variable)
ii) the distance the ball travels from the ramp before falling to the ground (dependent variable)
The only option that contains and relates this two variables as carried out during the course of the experiment is option D.
To1. PE = mgh
PE potential energy
m mass
g 9.81
h height
P = PE / t
P power
t time
Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object.
Systems always have inputs and outputs.
Explanation:
That point is in northwestern Queensland province, in Australia.