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Viktor [21]
3 years ago
5

The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins

ide the furnace?
Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, \lambda=1.9\times 10^{-6}\ m

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

\lambda\propto \dfrac{1}{T}

or

\lambda=\dfrac{b}{T}

b = Wein's displacement constant

\lambda=\dfrac{2.93\times 10^{-3}}{T}

T=\dfrac{2.93\times 10^{-3}}{\lambda}

T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

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The positive end of battery 1 touching the negative end of battery 2 and wires connecting the negative of battery 1 to the light light bulb and the positive of battery 2 to the light bulb.

Explanation:

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3 years ago
The maximum pressure most organisms can survive is about 1000 times the atmospheric pressure. Only small, simple organisms such
Schach [20]

Answer:

h = 10000 m

Explanation:

The pressure applied at a depth of the liquid is given by:

P =ρgh

where,

P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)

P = (1000)(101325 Pa) = 1.01 x 10⁸ Pa

ρ = Density of sea water = 1025 kg/m³

g = 9.8 m/s²

h = maximum depth to survive = ?

Therefore,

1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h

h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)

<u>h = 10000 m</u>

6 0
3 years ago
To make sure you understand how to use the equation, suppose that there are 1000 habitable planets in our galaxy, that 1 in 10 h
krok68 [10]

Answer:

5

Explanation:

Number of habitable planets = 1000

Fraction of planet with life = 1/10

Fraction of planet with life and civilization (before) = 1/4

Fraction of planet with life and civilization (now) =1/5

Therefore multiplying we have:

1000×1/10×1/4×1/5 = 5

5 0
3 years ago
The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele
Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 m/sec^2      

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion v^2=u^2+2as

553^2=0^2+2\times a\times 0.855

a=178835.6m/sec^2

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3 years ago
With respect to the earth, object 1 is moving at speed 0.80 c to the right. Object 2 is moving in the same direction at speed 0.
viktelen [127]

Answer:

0.976 c

Explanation:

v_{1e} = velocity of object 1 relative to earth = 0.80 c

v_{21} = velocity of object 2 relative to object 1 = 0.80 c

v_{2e} = velocity of object 2 relative to earth

Velocity of object 2 relative to earth is given as

v_{2e}= \frac{v_{1e} + v_{21}}{1 + \frac{v_{1e}v_{21}}{c^{2}}}

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v_{2e} = 0.976 c

6 0
3 years ago
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