All categories

3 years ago

HURRY BRAINLIEST!!!

Physics

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer:

oil-1st

water-2nd

honey-3rd

Explanation:

hope this helps!

You might be interested in

What happens when a blaring siren moves away from you

Anit [1.1K]

It gets quieter as the sound waves have to travel further and so the volume decreases

4 0

4 years ago

*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude

kvv77 [185]

Answer:

Approximately $3.86\; {\rm N}$ (given that the magnitude of this charge is $-7.35\; {\rm \mu C}$ .)

Explanation:

If a charge of magnitude $q$ is placed in an electric field of magnitude $E$ , the magnitude of the electrostatic force on that charge would be $F = E\, q$ .

The magnitude of this charge is $q = 7.35\; {\rm \mu C}$ . Apply the unit conversion $1\; {\rm \mu C} = 10^{-6}\; {\rm C}$ :

$\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}$ .

An electric field of magnitude $E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}}$ would exert on this charge a force with a magnitude of:

$\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}$ .

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

4 0

2 years ago

A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300

adell [148]

Answer:

v = 306.76 Km/h

Explanation:

given,

height of the aircraft = 3000 m

differential pressure reading = 3300 N/m²

density of air = 0.909 Kg/m³

speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

$\dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}$

where ρ is the density of the air at 3000 m

$v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}$

$v= \sqrt{\dfrac{2 \times 3300}{0.909}}$

$v = \sqrt{7260.726}$

v = 85.21 m/s

$v= 85.21 \times \dfrac{3600}{1000}$

v = 306.76 Km/h

4 0

3 years ago

How is a theory different from a hypothesis?

monitta

Answer:

A theory is a system of ideas intended to explain something, and a hypothesis is an educated guess.

Explanation: Hope this Helps! :)

6 0

4 years ago

A planet follows an elliptical orbit that brings it as close as 21 million km to a star and as far as 75 million km from the sta

nexus9112 [7]

Answer:

Explanation:

In an elliptical orbit , the angular momentum of the planet remains constant because velocity of planet makes a right angle to the direction to the star .

mvr = constant .

mv₁r₁ = mv₂r₂

v₁r₁ = v₂r₂

v₁ x 21 = 38 x 75

v₁ = 135.71 km/s .

6 0

3 years ago