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andrew11 [14]
3 years ago
6

Britney is solving a quadratic equation. Her first

Mathematics
2 answers:
Liula [17]3 years ago
8 0

Britney used commutative property of addition and distributive property of multiplication  over addition to get to step

The answer is II and IV ⇒ answer 4

Step-by-step explanation:

The quadratic equation is:

3x² - 8 - 10x = 3(2x + 3)

Britney's step is:

3x² - 10 x - 8 = 6x + 9

Lets explain the meaning of:

1. Commutative property of addition is: you can add a and b or b and a

   both give the same answer

2. Distributive property of multiplication over addition is: when the

   number a is multiplied by the sum of two numbers (b + c), the

   first number a can be distributed to both b and c and multiplied

   by each of them separately, then adding the two products ab and

   ac together for the same result as multiplying the first number a by

   the sum (b + c) ⇒ a(b + c) = ab + ac

3. Addition property of equality is: the property that states if you

   add the same number to both sides of an equation, the sides

   remain equal

4. Multiplication property of equality is: The property that states if

   you multiply both sides of an equation by the same number, the

   sides remain equal

Now let us explain Britney's step

∵ She change the places of the terms - 10x and - 8

- She arranges the terms of the left hand side from greatest power

  of x to the numerical term

∴ She used the commutative property of addition

∵ She multiplied 3 by 2x and multiplied 3 by 3

- She multiplied the number out side the bracket by each of the

  two terms in the bracket

∴ She used the distributive property of multiplication over addition

Britney used commutative property of addition and distributive property of multiplication  over addition to get to step

The answer is number 4) II and IV

Learn more:

You can learn more about quadratic equation in brainly.com/question/8196933

#Learn withBrainly

KiRa [710]3 years ago
5 0

Answer:

4) II and IV

Step-by-step explanation:

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Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

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where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to V(t)^{2}. Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

\frac{dr(t)}{dt}  = B*\sqrt{r(t)}

Here again appears a constant B for the "proportional" part. And i wrote the velocity as \frac{dr(t)}{dt} "the rate of change of the position with respect to te time".

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3 years ago
A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

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Answer:

-  \frac{23}{10}

Step-by-step explanation:

\frac{2}{5}  \div  \frac{ - 1}{2}  -  \frac{3}{2}

➡️ -  \frac{2}{5}  \times 2 -  \frac{3}{2}

➡️ -  \frac{4}{5}  -  \frac{3}{2}

➡️ -  \frac{23}{10}

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