Answer:
dado os monômios X elevado a 2 + 2 elevado a 2 menos 6 elevado a 2 a redução dos monômios está representado na questão em que os monômios a seguir eles representam quatro graus dê valor numérico da expressão m + n = 20 x elevado a 7 Y.
T = 3 h = 3 x 3600s = 10800s
d = 100 x 10800 = 1080000km to The east.
Answer:
a. Wgra=786.09J
b. 1.28m
Explanation:
The change in the potential energy is the work done by the gravitational force.
For this problem you have to take into account that the total work done is given by the change in the kinetic energy
Furthermore the total work is the contribution of the work done by the skater, the gravitational force and the friction
(a) by separating Wfric you have
(b) It is only necessary to use the expression for the work done by gravitational force
HOPE THIS HELPS!!
<span>a. The magnitude of the vector is doubled as well.
Let's say we have a 2-dimensional vector with components x and y.
It's magnitude lâ‚ is given by:
lâ‚ = âš(x² + y²)
If we double the components x and y, the new magnitude lâ‚‚ is:
lâ‚‚ = âš((2x)² + (2y²))
With a bit of algebra...
lâ‚‚ = âš(4x² + 4y²)
lâ‚‚ = âš4(x² + y²)
lâ‚‚ = 2âš(x² + y²)
We can write the new magnitude lâ‚‚ in terms of the old magnitude lâ‚.
lâ‚‚ = 2lâ‚
Therefore, the new magnitude is double the old one.
It should be clear that this relationship applies to 3D (and 1D) vectors as well.
b. The direction angle is unchanged.
The direction angle θ₠for a 2-dimensional vector is given by:
θ₠= arctan(y / x)
If we double both components, we get:
θ₂ = arctan(2y / 2x)
θ₂ = arctan(y / x)
θ₂ = θâ‚
The new direction angle is the same as the old one.</span>
Gravitational pull changes between each planet while its the "MASS" which doesnt change
