Answer:
g=9.64m/s^2.
Explanation:
Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GMwhere G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3 is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).
Answer:
Angular displacement of the turbine is 234.62 radian
Explanation:
initial angular speed of the turbine is
![\omega_i = 2\pi f_1](https://tex.z-dn.net/?f=%5Comega_i%20%3D%202%5Cpi%20f_1)
![\omega_1 = 2\pi(\frac{610}{60})](https://tex.z-dn.net/?f=%5Comega_1%20%3D%202%5Cpi%28%5Cfrac%7B610%7D%7B60%7D%29)
![\omega_1 = 63.88 rad/s](https://tex.z-dn.net/?f=%5Comega_1%20%3D%2063.88%20rad%2Fs)
similarly final angular speed is given as
![\omega_f = 2\pi f_2](https://tex.z-dn.net/?f=%5Comega_f%20%3D%202%5Cpi%20f_2)
![\omega_2 = 2\pi(\frac{837}{60})](https://tex.z-dn.net/?f=%5Comega_2%20%3D%202%5Cpi%28%5Cfrac%7B837%7D%7B60%7D%29)
![\omega_2 = 87.65 rad/s](https://tex.z-dn.net/?f=%5Comega_2%20%3D%2087.65%20rad%2Fs)
angular acceleration of the turbine is given as
![\alpha = 5.9 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%205.9%20rad%2Fs%5E2)
now we have to find the angular displacement is given as
![\theta = \omega t + \frac{1}{2}\alpha t^2](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Comega%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2)
![\theta = (63.88)(3.2) + (\frac{1}{2})(5.9)(3.2^2)](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%2863.88%29%283.2%29%20%2B%20%28%5Cfrac%7B1%7D%7B2%7D%29%285.9%29%283.2%5E2%29)
![\theta = 234.62 radian](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20234.62%20radian)
B. In step 3
They incorrectly solved for x. It should have been x=-3 and x=5
Answer:
Explanation:
1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.
9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2
Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations. We are going to use vf = vi + at. Everything is just given, or we can assume, so I'll just solve.
vf = vi + at
vf = 0 + 127008 km/hour^2 * 24 hours
vf = 3,048,192 km/hour
If there's anything that doesn't make sense let me know.
It's a form of mechanical energy