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geniusboy [140]
3 years ago
15

Please answer the following two questions.

Physics
1 answer:
IceJOKER [234]3 years ago
8 0

The regions of Great Lakes that are having a localized maximum in snowfall are called: B. snowbelts.

<h3>What is a snowbelt?</h3>

A snowbelt can be defined as a geographical region (area) near the Great Lakes in North America that is typically characterized by heavy localized maximum in snowfall, especially off the southern and eastern shores.

This ultimately implies that, snowbelts are the regions of Great Lakes that are having a localized maximum in snowfall.

In conclusion, hurricanes are more likely to form in the tropical Atlantic during a La Nina year because it weakens the wind shear.

Read more on snowbelt here: brainly.com/question/10128335

#SPJ1

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Which sentence best describes a role of gravity in the formation of the
enyata [817]

Answer:

I think it's option D

Explanation:

I think it's option D but not so sure

8 0
3 years ago
The polar coordinates of the collar A are given as functions of time in seconds by r = 2+ 0.7 t2 ft and ????= 3.5t rad. What are
r-ruslan [8.4K]

Answer with explanation:

Part a)

v_{radial}=\frac{dr}{dt}=\frac{d(2+0.7t^{2})}{dt}\\\\v_{radial}=1.4t\\\\\therefore v_{radial}|_{t=4}=1.4\times 4=5.6ft/s\\\\v_{angular}=r|_{t=4}\times \frac{d\theta }{dt}=13.2\frac{3.5t}{dt}=46.2fts^{-1}\\\\\therefore v=\sqrt{v_{radial}^{2}+v_{angular}^{2}}\\\\v=46.53ft/s

Part b)

a_{radial}=\frac{d^{2}r}{dt^{2}}=\frac{d^{2}(2+0.7t^{2})}{dt^{2}}\\\\a_{radial}=1.4ft/s^{2}\\\\a_{angular}=r\times \frac{d^{2}\theta }{dt^{2}}\\\\a_{angular}=r\times \frac{d^{2}(3.5t) }{dt^{2}}\\\\\therefore a_{angular}=0\\\\\therefore Accleration=1.4ft/s^{2}

8 0
3 years ago
If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen dista
xxMikexx [17]

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

Y = \frac{\lambda L}{d}

where,

Y = Fringe spacing = ?

λ = wavelength = \frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz} = 8 x 10⁵ m

L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

Therefore,

Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}

<u>Y = 3.39 x 10⁶ m</u>

6 0
3 years ago
A crate feels a 277 n normal force as it sits on the ground. what is its mass?
Umnica [9.8K]

Answer:

28.3 kg

Explanation:

Assuming the ground is level, the normal force equals the weight.

N = mg

277 N = m × 9.8 m/s²

m = 28.3 kg

5 0
4 years ago
Read 2 more answers
Using a horizontal force of 200N,we intend to move a wooden cabinet across a floor at constant velocity.What is the friction for
IgorLugansk [536]

Answer:

-200 N

Explanation:

The cabinet moves at constant velocity, so that means there's no acceleration.

Applying Newton's second law to the cabinet:

∑F = ma

F + 200 = 0

F = -200

The friction force is 200 N in the opposite direction.

8 0
3 years ago
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