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2 years ago

[CM.01] Which states of matter appear only in the hydrosphere?

2 answers:

3 0

I will say liquid because the rest all consist of solids and atmosphere also contain gas, but only hydrosphere has liquid.

choli [55]2 years ago

3 0

Answer:

Liquid is the correct answer.

Explanation:

The hydrosphere contains the total amount of water on a planet. The water is on the surface, ground and in the atmosphere. Hydrosphere can be in liquid, gas and solid forms. On earth, the water exists in liquid form in lakes, oceans, and rivers. The frozen part of the water is in the form of an ice cap and icebergs. In hydrosphere, the water moves in a cycle. which leads to the transformation of water from one form to another, it is called the water cycle. The waterfalls in the form of rain and snow and are collected by lakes and ocean. It again evaporates into the atmosphere and the cycle starts again.

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What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?

notsponge [240]

The empirical formula for a compound is KClO3

Explanation
find the moles of each element
moles = % composition/molar mass

molar mass of of potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles of potassium = 31.9 / 39 = 0.818 moles
moles of chlorine = 28.9/35.5 = 0.814 moles
moles of oxygen = 39.2/ 16 = 2.45 moles

find the mole ratio by dividing with the smallest mole = 0.814 moles

potassium = 0.818/0.814 =1
chlorine = 0.814/0.814 = 1
oxygen = 2.45 /0.814 =3

the empirical formula is therefore = KClO3

7 0

3 years ago

if the lightbulb receives 100 J of electrical energy, and gives off 75 energy, how much heat (thermal energy away from the light

oksano4ka [1.4K]

Answer:

Amount of heat energy released by light bulb = 25 joules

Explanation:

Given:

Energy receive by light bulb = 100 Joules

Energy released by light bulb as light energy = 75 Joules

Find:

Amount of heat energy released by light bulb

Computation:

We know that, energy is neither be created nor destroys

So,

Using Law of conservation of energy

Energy receive by light bulb = Energy released by light bulb as light energy + Amount of heat energy released by light bulb

100 = 75 + Amount of heat energy released by light bulb

Amount of heat energy released by light bulb = 100 - 75

Amount of heat energy released by light bulb = 25 joules

8 0

2 years ago

Explain how a substances flammability can indicate a chemical change.

Marat540 [252]

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May I have brainliest please? :)

4 0

2 years ago

A chemist burns 0.8 g of iron in oxygen.

stich3 [128]

Answer:

0.3g

Explanation:

1.1 - 0.8 = 0.3

Hope this helps

7 0

2 years ago

why is it harder to remove an electron from fluorine than from carbon? to put it another way, why are the outermost electrons of

Verizon [17]

It is harder to remove an electron from fluorine than from carbon because the size of the nuclear charge in fluorine is larger than that of carbon.

The energy required to remove an electron from an atom is called ionization energy.

The ionization energy largely depends on the size of the nuclear charge. The larger the size of the nuclear charge, the higher the ionization energy because it will be more difficult to remove an electron from the atom owing to increased electrostatic attraction between the nucleus and orbital electrons.

Since fluorine has a higher size of the nuclear charge than carbon. More energy is required to remove an electron from fluorine than from carbon leading to the observation that; it is harder to remove an electron from fluorine than from carbon.

Learn more: brainly.com/question/16243729

6 0

2 years ago