All categories

2 years ago

What are three Possible overlaps that can occur during bond formation

Chemistry

1 answer:

mart [117]2 years ago

4 0

Answer:

The Sigma (σ) Bond

S-S Overlapping. In this kind of overlapping, one 's' orbital from each participating atom undergoes head-on overlapping along the internuclear axis. ...

S-P Overlapping. ...

P-P overlapping.

You might be interested in

What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum

klio [65]

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

3 0

3 years ago

Which of the following does not change the rate of collisions between particles in a reaction?

Naddik [55]

Answer: C

Explanation: trust me bro

4 0

3 years ago

Will mark brainliest for correct answer!!! Need help ASAP :"))

Andrews [41]

Answer:

So the balanced chemical equation would look like this:

4NO + 6 $H_{2}$ O -> 4N $H_{3}$ + 5 $O_{2}$

sorry i dont k how to find the moles when im already given a value :(

Explanation:

3 0

3 years ago

Sunflower oil contains 0.080 mol palmitic acid (C16H32O2)/mol, 0.060 mol stearic acid (C18H36O2)/mol, 0.27 mol oleic acid (C18H3

Cerrena [4.2K]

Answer:

$x_H=0.882$

$x_N=0.118$

Explanation:

In this reactor, oleic and linoleic acid react with hydrogen to form stearic acid. This reactions can be represented by:

Oleic: $C_{18}H_{34}O_2 (l) + H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)$

Linoleic: $C_{18}H_{32}O_2 (l) + 2 H_2 (g) \longrightarrow C_{18}H_{36}O_2 (l)$

Having this reactions in mind, the first thing is to determine the moles of hydrogen required:

Base of caculation: 1 mol of sunflower oil

For oleic acid: $n_{Holeic}=\frac{1 mol H_2}{1 mol oleic}*\frac{0.27 mol oleic}{1 mol oil}*\frac{335 mol oil}{hr}$

$n_{Holeic}=frac{90.45 mol H_2}{hr}$

For linoleic acid: $n_{Hlinoleic}=\frac{2 mol H_2}{1 mol linoleic}*\frac{0.59 mol linoleic}{1 mol oil}*\frac{335 mol oil}{hr}$

$n_{Holeic}=frac{395.3 mol H_2}{hr}$

$n_{Htotal}=\frac{90.45 mol H_2}{hr}+\frac{395.3 mol H_2}{hr}$

$n_{Htotal}=frac{485.75 mol H_2}{hr}$

Applying the excess:

$n_{Htotal}=frac{485.75 mol H_2}{hr}*1.65=801.48 mol$

Nitrogen: $n_N= 801.48 mol*\frac{0.05 mol N}{0.95 mol}$

$n_N= 42.2 mol N$

After the reactions:

$n_H=801.48 mol-485.75mol=315.73 mol$

and the nitrogen is inert.

Purge stream:

$n_total=42.2+315.73 mol=357.93 mol$

$x_H=\frac{315.73mol}{357.93mol}=0.882$

$x_N=\frac{42.2mol}{357.93mol}=0.118$

4 0

3 years ago

PLEASE HELP! an element with 8 protons and 10 neutrons

leva [86]

Answer:

oxygen ion O2-

Explanation:

because it has 8 protons and gave gained 2 electron so O2-.

6 0

3 years ago

What are three Possible overlaps that can occur during bond formation​

What are three Possible overlaps that can occur during bond formation