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3 years ago

The chemical equation below is correctly balanced.

Chemistry

1 answer:

DIA [1.3K]3 years ago

8 0

Answer:

44.8 L of O2 will react (option D)

Explanation:

Step 1: Data given

Number of moles of SO2 = 4.00 moles

STP = Pressure = 1 atm and temperature = 273 K

Step 2: The balanced equation

2 SO2(g) + O2(g) → 2 SO3(g)

Step 3: Calculate moles of O2

For 2 moles SO2, we need 1 mol O2 to produce 2 moles SO3

For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2

Step 4: Calculate volume of O2

For 1 mol we have a volume of 22.4 L

V = (n*R*T)/ p

V = (2.00 * 0.08206 * 273)/p

V = 44.8 L

For 2.00 moles we have a volume of 2*22.4 = 44.8 L

44.8 L of O2 will react (option D)

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Manganese(iv) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3mno2+4al→3mn+2al2o3part awhat mass of

Oxana [17]

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3 years ago

The chemical reaction in which solid calcium oxide is treated liquid water is an example of what: A) decomposition B)combustion

laiz [17]

Answer:

The chemical reaction in which solid calcium oxide is treated liquid water is an example of Synthesis reaction. Hence, the answer is (D) Synthesis.

Explanation:

The formula of Calcium Oxide is CaO.

The formula of liquid water is H₂O.

Calcium Oxide reacts with water and forms Calcium Hydroxide. The Chemical equation is shown below.

CaO + H₂O --> Ca(OH)₂.

This is a Synthesis reaction because Ca(OH)₂ is synthesized by using Calcium Oxide and water.

The product of this reaction is calcium hydroxide, also known as slaked lime.

Thus, when calcium oxide reacts with water, slaked lime is produced.

Calcium oxide is also known as lime and is most commonly used for many purposes. It can be used for pH correction of water or for its disinfection (with excess lime).

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3 years ago

What is the empirical formula of a compound containing 40.0% sulfur and 60.0% oxygen by mass?

gizmo_the_mogwai [7]

in order to determine empirical formula we have to determine the mole ratio of the given elements

Let the total mass of the compound is 100g

as given that the compound has 40% sulfur , so mass of sulfur = 40g

as given that the compound has 60% oxygen, so mass of oxygen = 60g

let us calculate the moles of each element

Moles of sulfur = mass / atomic mass = 40 / 32 = 1.25

moles of oxygen = mass / atomic mass = 60/ 16 = 3.75

In order to get simple ratio of moles we will divide both the moles with least number of moles which is 1.25

moles of sulfur = 1.25 / 1.25 = 1

moles of oxygen = 3.75 /1.25 = 3

So empirical formula will be SO₃

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2 years ago

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Marizza181 [45]

Answer:

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Explanation:

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3 years ago

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alekssr [168]

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