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Nimfa-mama [501]
3 years ago
13

The chemical equation below is correctly balanced.

Chemistry
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

44.8 L of O2 will react (option D)

Explanation:

Step 1: Data given

Number of moles of SO2 = 4.00 moles

STP = Pressure = 1 atm  and temperature = 273 K

Step 2: The balanced equation

2 SO2(g) + O2(g) → 2 SO3(g)

Step 3: Calculate moles of O2

For 2 moles SO2, we need 1 mol O2 to produce 2 moles SO3

For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2

Step 4: Calculate volume of O2

For 1 mol we have a volume of 22.4 L

V = (n*R*T)/ p

V = (2.00 * 0.08206 * 273)/p

V = 44.8 L

For 2.00 moles we have a volume of 2*22.4 = 44.8 L

44.8 L of O2 will react (option D)

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An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,
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Answer: The original volume in liters was 0.0707L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.85 atm

P_2 = final pressure of gas = 456 mm Hg = 0.60 atm   (760mmHg=1atm)

V_1 = initial volume of gas = ?

V_2 = final volume of gas = 94.0 ml

T_1 = initial temperature of gas = 66^oC=273+66=339K

T_2 = final temperature of gas = 113^oF=318K  (32^0F=273K)

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\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}

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