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ryzh [129]
2 years ago
13

Choose the correct products for the double replacement reaction below. Click here to access the solubility rules to determine wh

ich product, if any, forms a solid precipitate in the reaction. PbCl2 MgSO4Upper C subscript 3 upper H subscript 8 plus upper O subscript 2 right arrow. ? Pb O2 MgCl PbMg ClSO4 PbSO4 MgCl2 Pb(SO4)2 MgCl.
Chemistry
2 answers:
Lemur [1.5K]2 years ago
8 0

MgCl₂ & PbSO₄ is the correct product for the given double replacement reaction.

<h3>What is double displacement reaction?</h3>

In the double displacement reaction displacement of two substrate will take place among two reactants and formation of products takes place.

In the question, PbCl₂ reacts with MgSO₄ and displacement between the cations takes place and formation of  MgCl₂ and insoluble precipitate PbSO₄ is formed.

Given reaction is represented as:

PbCl₂ + MgSO₄ → MgCl₂ + PbSO₄

According to the activity series, reactivity of Magnesium is more as compared to the lead atom. So lead is displaced by the magnesium atom and form the above given products.

Hence, option (3) is correct i.e. MgCl₂ & PbSO₄.

To know more about double displacement reaction, visit the below link:

brainly.com/question/26413416

SIZIF [17.4K]2 years ago
8 0

Answer:

its C then B

Explanation:

just took the assignment

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Why methyl orange in basic medium is yellow and why it is red in acidic medium?​
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The products in a decomposition reaction _____.
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URGENT!!! A solution in which there is very little solute dissolved in a solvent.
ella [17]

Answer:

Is called a diluted solution

Explanation:

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4 0
3 years ago
Match the following aqueous solutions with the appropriate letter from the column on the right.1. 0.19 m AgNO3 2. 0.17 m CrSO4 3
vichka [17]

Answer:

0.13 m of Mn(NO_3)_2 → Highest boiling point

0.19 m of AgNO_3 → Second  Highest boiling point

0.17 m of CrSO_4 → Third highest boiling point

0.31 m Sucrose (nonelectrolyte)  → Lowest boiling point

Explanation:

Elevation in boiling is given by :

\Delta T_b=i\times k_b\times m

Where :

i = van't Hoff factor

k_b= Molal Elevation constant of solvent

m = molaity of the solution

1) 0.19 m of AgNO_3

AgNO_3\rightarrow Ag^++NO_3^{-}

i = 2 (electrolyte)

Molality of the solution = 0.19

Elevation is boiling point of solution:

\Delta T_b=2\times k_b\times 0.19 m

\Delta T_b=0.38 m\times k_b

2) 0.17 m of CrSO_4

CrSO_4\rightarrow Cr^{2+}+SO_4^{2-}

i = 2 (electrolyte)

Molality of the solution = 0.17

Elevation is boiling point solution :

\Delta T_b=2\times k_b\times 0.17 m

\Delta T_b=0.34 m\times k_b

3) 0.13 m of Mn(NO_3)_2

Mn(NO_3)_2\rightarrow Mn^{2+}+2NO_3^{-}

i = 3 (electrolyte)

Molality of the solution = 0.13

Elevation is boiling point solution :

\Delta T_b=3\times k_b\times 0.13 m

\Delta T_b=0.39 m\times k_b

4) 0.31 m Sucrose (nonelectrolyte)

i = 1 ( non electrolyte)

Molality of the solution = 0.31 m

Elevation is boiling point solution :

\Delta T_b=1\times k_b\times 0.31 m

\Delta T_b=0.31 m\times k_b

Higher the value of elevation in temperature higher will be the boiling point of the solution .

The decreasing order of solution from highest boiling point to lowest boiling point is :

0.39 m\times k_b>0.38 m\times k_b>0.34 m\times k_b>0.31 m\times k_b

0.13 m of Mn(NO_3)_2 → Highest boiling point

0.19 m of AgNO_3 → Second  Highest boiling point

0.17 m of CrSO_4 → Third highest boiling point

0.31 m Sucrose (nonelectrolyte)  → Lowest boiling point

6 0
3 years ago
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