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Ket [755]
3 years ago
9

The transfer of thermal energy between two bodies at different temperatures is known as

Chemistry
1 answer:
EastWind [94]3 years ago
3 0
Conduction.......................
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Select the true statement. ANSWER Unselected Anions are smaller than their neutral parent atoms because there are fewer electron
Olenka [21]

Answer:

Explanation:

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3 0
4 years ago
Hello, everyone!
marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the <em>law of ideal gases,</em>  

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x \frac{1 g}{1000 mg} x \frac{1 mol}{28.01 g}

→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V =  \frac{0.00125 mol x 0.082057 \frac{atm L}{mol K}  x 243 K}{0.92 atm}

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x \frac{1000 cm^{3} }{1 L} = 27.09 cm³

<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>

c = 27 cm³ / m³ = 27 ppm

<u>To express this concentration in percent by volume </u>we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 \frac{cm^{3} }{m^{3} } x \frac{1 m^{3} }{1 000 000 cm^{3} } x 100%

c = 0.003 %

So, <u>the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is </u>27.09 ppm and 0.003 %.

5 0
3 years ago
Under which conditions would the solubility of a gas be greatest? high pressure and high temperature high pressure and low tempe
kiruha [24]

Option B: high pressure and low temperature

A gas is more soluble under high pressure and low temperature conditions.

On increasing temperature of a gas, its kinetic energy increases. The increase in kinetic energy increases the motion of particles of gas this causes most of the gaseous particles to escape from the gas phase. Thus, less particles are available to dissolve in liquid and solubility decreases.

The effect of pressure on solubility of gas can be explained with the help of Henry's law. According to the law, at constant temperature, solubility of gas and partial pressure of gas are related to each other as follows:

p=k_{h}c

Here, p is the partial pressure of the gas, k_{h} is Henry's law constant, and

c is the concentrate of the gas.

According to above relation, concentration of gas decreases on decreasing partial pressure. Thus, on increasing pressure,  concentration of gas increases this increases the solubility of gas in liquid.

Therefore, solubility of gas is greatest at high pressure and low temperature.


4 0
4 years ago
Read 2 more answers
The diagram shows three isotopes. What element is represented?
lisov135 [29]

Answer:

Where is the diagram?please put the pictu

3 0
3 years ago
Read 2 more answers
If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
n200080 [17]
<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span> 
</span>
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
              = 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴ 
where Ca is the acid concentration 
5 0
3 years ago
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