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3 years ago

Approximate the instantaneous rate of this reaction at time t = 40 s.

1 answer:

6 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Find the slope at t = 40, points (0, 0.48) and (70, 0.24).
Slope= Δy= (0.24 – 0.48)=– 0.0034 M/s
Δx(70 – 0)
<span>
(the negative represent direction so the answer is positive)</span>

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Ice floats in water because it _____. is less dense than water contains more oxygen than water has a higher pH than water has mo

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Answer:

it is less dense than water

Explanation:

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3 years ago

A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To

Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

Mass of Mg(NO₃)₂ (solute): 42.0 g

Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

Step 3: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.283 mol / 0.259 L

M = 1.09 M

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3 years ago

Identify how many of the original parent nuclei remain after three half-lives

Nutka1998 [239]

Answer:

yes

Explanation:

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3 years ago

Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be

vlabodo [156]

Answer:

The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.

Explanation:

Mass of bottle = 10.221 g

Mass of bottle with aluminium pieces = 11.353 g

Mass of aluminium = 11.353 g - 10.221 g = 1.132 g

Mass of alum and bottle = 19.230 g

Mass of alum = 19.230 g - 10.221 g = 9.009 g

Experimental yield of alum = 9.009 g

Theoretical yield of alum:

$2Al(s) +2 KOH(aq) +4H_2SO_4(aq)+10 H_2O(l) \rightarrow 2 KAl(SO_4)_2.12 H_2O(s)+3H_2(g)$

Moles of aluminium = $\frac{1.132 g}{27 g/mol}=0.041926 mol$

According to reaction, 2 moles of aluminum gives 2 moles of alum.

Then 0.041926 mol aluminium will give :

$\frac{2}{2}\times 0.041926 mol=0.041926 mol$ of alum.

Mass of 0.041926 moles of alum:

0.041926 mol × 474 g/mol= 19.873 g

Theoretical yield of alum = 19.873 g

Percentage yield:

$\% Yield =\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of the alum:

$\% Yield =\frac{ 9.009 g}{19.873 g}\times 100=45.33\%$

The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.

7 0

4 years ago

(a) The student dissolves the entire impure sample of CuSO4(s) in enough distilled water to make 100.mL of solution. Then the st

Talja [164]

Answer:

Explanation:

Given parameters :

Volume of solution = 100mL

Absorbance of solution = 0.30

Unknown:

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Solution:

There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.

A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.

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A = ε mC l

where εm is the molar extinction coefficient

C is the concentration

l is the path length

Since the εm is not given and assuming path length is 1;

Then we solve for the concentration.

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3 years ago