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Digiron [165]
3 years ago
7

How many moles are equivalent to 365 g of aluminum chloride? Using the dimensions analysis. Show work

Chemistry
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

≈ 2.74 mol AlCl_{3}

(I rounded to 3 sig figs because the starting amount has 3 sig figs.)

Explanation:

\frac{365g   AlCl_{3}}{1}*\frac{1    mol    AlCl_{3}}{133.34g AlCl_{3}} = 2.73736313184 mol AlCl_{3} ≈ 2.74 mol AlCl_{3}

Hope this helps!

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If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O
Zanzabum

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ = \frac{Mass}{Molar mass}

                                          = \frac{2.2}{44}

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Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number}

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0.03 gram atom of sulphur means 0.03 moles of sulphur.

Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

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0.0076kg

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To get the mass, we use the relation among density, mass and volume.

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Here mass? , density = 0.779g/ml , volume = 9.76ml

Mass = 9.76 * 0.779 = 7.60g

Answer is wanted in kg so we divide by 1000. This is 7.60/1000 = 0.0076kg

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