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My name is Ann [436]
4 years ago
14

The stock solution of hydrochloric acid is 12.0M HCI. If the teacher starts with 130 ml of this concentrated acid, what volume o

f 3.0M HCI can be prepared?
Chemistry
1 answer:
tatyana61 [14]4 years ago
6 0

Answer:

520mL

Explanation:

Data obtained from the question include:

Molarity of stock solution (M1) = 12M

Volume of stock solution (V1) = 130mL

Molarity of diluted solution (M2) = 3M

Volume of diluted (V2) =..?

The volume of the diluted solution can be obtained as follow:

M1V1 = M2V2

12 x 130 = 3 x V2

Divide both side by 3

V2 = 12 x 130 / 3

V2 = 520mL.

Therefore, 520mL of the diluted solution can be prepared.

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Which chemical formula corresponds to this structural formula? c6h6h6h2 c14h6 c6h12 c6h14
Alexxandr [17]

The chemical formula C₂H₆O, which is designated as option D, is equivalent to this structural formula.

<h3><u>What is a Chemical Formula ?</u></h3>

Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus (+) and minus () signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.

  • An empirical formula represents by symbols, such as Na for sodium and Cl for chlorine, with subscripts that show the relative number of atoms in each.
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brainly.com/question/26388921

6 0
1 year ago
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What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate
Katena32 [7]

Explanation:

N(Ca)=3×N(Ca₃(PO₄)₂)=

=3×2.3×10²³=6.9×10²³

6.02×10²³→40g

6.9×10²³→Xg

m(Ca)=X≈45.85g

3 0
3 years ago
What is NaHCO3 = Na2CO3 + H2O + CO2 as a balanced equation?
ollegr [7]
Balanced equation = 2 NaHCO3 —-> Na2CO3 + H2O + CO2

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3 years ago
What does the symbol Pt mean in a chemical equation in chemistry?
uysha [10]

Explanation:

It is mean Platinum .

hope to helped.

5 0
3 years ago
The Henry's law constant (kH) for O2 in water at 20°C is 1.28 × 10−3 mol/(L·atm). (a) How many grams of O2 will dissolve in 4.00
Burka [1]

Answer:

Solubility of O₂(g) in 4L water = 3.42 x 10⁻² grams O₂(g)

Explanation:

Graham's Law => Solubility(S) ∝ Applied Pressure(P) => S =k·P

Given P = 0.209Atm & k = 1.28 x 10⁻³mol/L·Atm

=> S = k·P = (1.28 x 10⁻³ mole/L·Atm)0.209Atm = 2.68 x 10⁻³ mol O₂/L water.

∴Solubility of O₂(g) in 4L water at 0.209Atm = (2.68 x 10⁻³mole O₂(g)/L)(4L)(32 g O₂(g)/mol O₂(g)) = <u>3.45 x 10⁻² grams O₂(g) in 4L water. </u>

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3 years ago
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