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4 years ago

What is the percent composition by mass of oxygen in Ca(NO3)2 (gram-formula= 164 g/mol)?

1 answer:

5 0

To find this, we will use this formula:

Molar mass of element
------------------------------------ x 100
Molar mass of compound

So, first lets calculate the mass of the compound as a whole. We use the atomic masses on the periodic table to determine this.

Ca: 40.078 g/mol
N2 (there is two nitrogens): 28.014 g/mol
O6 (there are six nitrogens: 3 times 2): 95.994 g/mol

When we add all of those numbers up together, we get 164.086. That is the molar mass for the whole compound. However, we are trying to figure out what percent of the compound oxygen makes up. From the molar mass, we know that 95.994 of the 164.086 is oxygen. Lets plug those numbers into our equation!

95.994
-----------
164.086

When we divide those two numbers, we get .585. When we multiply that by 100, we get 58.5.

So, the percent compostition of oxygen in Ca(NO3)2, or, calcium nitrate, is 58.5%.

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Determine the maximum number of electrons that can be found in each of the following subshells: a. 3s b. 3d c. 4p d. 4f.

monitta

Answer:

a. 2

b. 10

c. 6

d. 14

Explanation:

The maximum number of the electrons which can be filled in the s orbital are:- 2

The maximum number of the electrons which can be filled in the p orbital are:- 6

The maximum number of the electrons which can be filled in the d orbital are:- 10

The maximum number of the electrons which can be filled in the f orbital are:- 14

Thus,

a. 3s can have maximum of 2 electrons.

b. 3d can have maximum of 10 electrons.

c. 4p can have maximum of 6 electrons.

d. 4f can have maximum of 14 electrons.

3 0

3 years ago

The atomic theory has been revised many times over the last several hundred years. John Dalton described the atom as a solid sph

frez [133]

As new discoveries are made, existing theories are revised or replaced.

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3 years ago

Read 2 more answers

Which of the following would most likely be found in the outer cloud region?

Likurg_2 [28]

Answer:

there is no "following". if you can attach an image for me, ill be glad to help.

Explanation:

have a good day,

~evita

6 0

3 years ago

An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th

Vladimir [108]

Answer: The molarity of $NO_3^-$ ions in the solution is 0.306 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute $(Cu(NO_3)_2.6H_2O)$ = 15.6 g

Molar mass of $(Cu(NO_3)_2.6H_2O)$ = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

$\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M$

As, 1 mole of $(Cu(NO_3)_2.6H_2O)$ produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of $NO_3^-$ ions = (2 × 0.153) = 0.306 M

Hence, the molarity of $NO_3^-$ ions in the solution is 0.306 M

3 0

3 years ago

PLEASE Answer asap! What characteristics are shared by all alkali metals and alkaline earth metals?

agasfer [191]

Answer:

Explanation:

Mostly all of them but most likely C

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3 years ago