The answer is the plague, or the black death
The amount of heat lost by the copper is 2402.4 J.
To Calculate the amount of heat lost, we use the formula below.
<h3>Formula:</h3>
- Q = cm(t₂-t₁)................. Equation 1
<h3>Where:</h3>
- Q = Amount of heat lost
- c = specific heat capacity of copper
- m = mass of copper
- t₂ = Final temperature
- t₁ = Initial temperature
From the question,
<h3>Given:</h3>
- m = 78 g
- c = 0.385 J/g°C
- t₂ = 120°C
- t₁ = 40°C
Substitute these values into equation 1.
- Q = 78(0.385)(120-40)
- Q = 2402.4 J
Hence, The heat lost by the copper is 2402.4 J
Learn more about heat here: brainly.com/question/13439286
B) the bacteria that live in the intestine of a rabbit
That statement is False.
Most metals are in the solid state at room temperature. The only metal that is in liquid state in the room temperature is Mercury, (Hg)
Answer:
Isopropyl propionate
Explanation:
1. Information from formula
The formula is C₆H₁₂O₂. A six-carbon alkane would have the formula C₆H₁₄. The deficiency of two H atoms indicates the presence of either a ring or a double bond.
2. Information from the spectrum
(a) Triplet-quartet
A 3H triplet and a 2H quartet is the classic pattern for a CH₃CH₂- (ethyl) group
(b) Septet-doublet
A 1H septet and a 6H doublet is the classic pattern for a -CH(CH₃)₂ (isopropyl) group
(c) The rest of the molecule
The ethyl and isopropyl groups together add up to C₇H₁₂.
The rest of the molecule must have the formula CO₂ and one unit of unsaturation. That must be a C=O group.
The compound is either
CH₃CH₂-COO-CH(CH₃)₂ or (CH₃)₂CH-COO-CH₂CH₃.
(d) Well, which is it?
The O atom of the ester function should have the greatest effect on the H atom on the adjacent carbon atom.
The CH of an isopropyl is normally at 1.7. The adjacent O atom should pull it down perhaps 3.2 units to 4.9.
The CH₂ of an ethyl group is normally at 1.2. The adjacent O atom should pull it down to about 4.4.
We see a signal at 5.0 but none near 4.4. The compound is isopropyl propionate.
3. Summary
My peak assignments are shown in the diagram below.