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LUCKY_DIMON [66]
1 year ago
8

Please help with this question!

Chemistry
1 answer:
joja [24]1 year ago
4 0

Answer:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

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What was the name of the disease that killed nearly half the people of Europe?
Licemer1 [7]
The answer is the plague, or the black death
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3 years ago
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How much heat has been lost when a 78 g piece of copper is placed into a calorimeter and cools from 120°C to
lora16 [44]

The amount of heat lost by the copper is 2402.4 J.

To Calculate the amount of heat lost, we use the formula below.

<h3>Formula:</h3>
  • Q = cm(t₂-t₁)................. Equation 1

<h3>Where:</h3>
  • Q = Amount of heat lost
  • c = specific heat capacity of copper
  • m = mass of copper
  • t₂ = Final temperature
  • t₁ = Initial temperature

From the question,

<h3>Given:</h3>
  • m = 78 g
  • c = 0.385 J/g°C
  • t₂ = 120°C
  • t₁ = 40°C

Substitute these values into equation 1.

  • Q = 78(0.385)(120-40)
  • Q = 2402.4 J

Hence, The heat lost by the copper is 2402.4 J

Learn more about heat here: brainly.com/question/13439286

3 0
2 years ago
Assessment started: undefined.
Vilka [71]
B) the bacteria that live in the intestine of a rabbit
6 0
3 years ago
Most metals are in the liquid state at room temperature.
Alexxandr [17]
That statement is False.

Most metals are in the solid state at room temperature. The only metal that is in liquid state in the room temperature is Mercury, (Hg)
7 0
3 years ago
The 1H-NMR of a compound with molecular formula C6H12O2 consists of four signals: 1.1 (triplet, integrating to 3 Hydrogens), 1.2
Tamiku [17]

Answer:

Isopropyl propionate  

Explanation:

1. Information from formula

The formula is C₆H₁₂O₂. A six-carbon alkane would have the formula C₆H₁₄. The deficiency of two H atoms indicates the presence of either a ring or a double bond.

2. Information from the spectrum

(a) Triplet-quartet

A 3H triplet and a 2H quartet is the classic pattern for a CH₃CH₂- (ethyl) group

(b) Septet-doublet

A 1H septet and a 6H doublet is the classic pattern for a -CH(CH₃)₂ (isopropyl) group

(c) The rest of the molecule

The ethyl and isopropyl groups together add up to C₇H₁₂.

The rest of the molecule must have the formula CO₂ and one unit of unsaturation. That must be a C=O group.

The compound is either

CH₃CH₂-COO-CH(CH₃)₂ or (CH₃)₂CH-COO-CH₂CH₃.

(d) Well, which is it?

The O atom of the ester function should have the greatest effect on the H atom on the adjacent carbon atom.

The CH of an isopropyl is normally at 1.7. The adjacent O atom should pull it down perhaps 3.2 units to 4.9.  

The CH₂ of an ethyl group is normally at 1.2. The adjacent O atom should pull it down to about 4.4.

We see a signal at 5.0 but none near 4.4. The compound is isopropyl propionate.

3. Summary

My peak assignments are shown in the diagram below.

4 0
3 years ago
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