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3 years ago

How many grams are there in a 14.5 moles lithium permanganate

Chemistry

1 answer:

frutty [35]3 years ago

5 0

There are 1825.6 g in a 14.5 moles Lithium permanganate

<h3> Further explanation</h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass :

$\tt mol=\dfrac{mass}{MW}$

moles of Lithium permanganate = 14.5

Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

$\tt mass=mol\times MW\\\\mass=14.5\times 125.9~g/mol\\\\mass=1825.6~g$

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Read 2 more answers

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<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

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Relationship between $K_p\text{ and }K_c$ is given by the expression:

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4 years ago

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