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kompoz [17]
3 years ago
8

How many grams are there in a 14.5 moles lithium permanganate

Chemistry
1 answer:
frutty [35]3 years ago
5 0

There are 1825.6 g in a 14.5 moles Lithium permanganate

<h3> Further explanation</h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass :

\tt mol=\dfrac{mass}{MW}

moles of Lithium permanganate = 14.5

Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

\tt mass=mol\times MW\\\\mass=14.5\times 125.9~g/mol\\\\mass=1825.6~g

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