Answer:
The concentration of the copper(II) sulfate solution is 0.99 M
Explanation:
Step 1: Data given
Mass of copper(II) sulfate = 79 grams
Volume of the flask = 500 mL
Molar mass copper(II) sulfate = 159.61 g/mol
Step 2: Calculate moles copper(II) sulfate
Moles CuSO4 = Mass CuSO4 / molar mass CuSO4
Moles CuSO4 = 79.0 grams / 159.61 g/mol
Moles CuSO4 = 0.495 moles
Step 3: Calculate concentration
Concentration CuSO4 = moles / volume
Concentration CuSO4 = 0.495 moles / 0.5 L
Concentration = 0.99 M
The concentration of the copper(II) sulfate solution is 0.99 M
Finding neutrons = Mass number - proton number.
For finding neutrons for phosphorus = 31-15
=16.
Answer:
See explanation
Explanation:
We know that in the presence of strong oxidizing agents such as permanganate , aldehydes are oxidized. This oxidation is often accompanied by a colour change.
The colour change in the permanganate oxidation of benzaldehyde is caused by the inorganic permangate. The colour changes from purple to colourless because Mn^7+ is reduced to Mn^2+.
The benzaldehyde is readily oxidized to benzoic acid in the presence of permanganate.
Answer:
The answer should be Sodium chloride
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