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-BARSIC- [3]
3 years ago
13

The concentration of two reactants is decreased by the same amount. How

Chemistry
1 answer:
IrinaVladis [17]3 years ago
5 0
I think answer should be d. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks
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An unknown or changeable quantity is called a(n)...
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3 years ago
When 240 mg of a certain molecular compound X are dissolved in 35.0 g of dibenzyl ether ((C6H5CH2)2O), the freezing point of the
DedPeter [7]

Answer: MM = 16.55 g/mol

Explanation: <u>Freezing</u> <u>point</u> <u>depression</u> is a phenomena that explains why adding a solute to a solvent decreases the solvent freezing point: when a substance begins to freeze, its molecules slows down and rearrange itself forming a solid. If a solute is added, the molecules from the solvent interfere in the formation of the solid. To guarantee the transformation, the solution has to cooled down even more.

Freezing point and molality concentration is related by

\Delta T=T_{f}_{(solvent)}-T_{f}_{(solution)}=K_{f}.m

where

ΔT is freezing point depression

T_{f}_{(solvent)} and T_{f}_{(solution)} are freezing point of solvent and solution, respectively

K_{f} is freezing point depression constant

m is molality concentration

<u />

Dibenzyl ether is the solvent and has the following properties: K_{f}= 6.27 and T_{f} = 3.6°C.

Molality concentration is

m=\frac{T_{(solvent)}-T_{(solution)}}{K_{f}}

m=\frac{3.6-1}{6.27}

m = 0.415

<u>Molality</u> <u>concentration</u> is moles (n) of solute dissolved in a mass, in kilogram, of solvent.

m=\frac{moles}{mass(kg)}

n = m(mass of solvent in kg)

n = 0.415(0.035)

n = 0.0145

<u>Molar</u> <u>mass</u> (M) is the weight of one sample mole and can be calculated as

n=\frac{m}{M}

M = \frac{m}{n}

m in grams

Molar mass of compound X is

M=\frac{0.24}{0.0145}

M = 16.55

<u>Molar mass of molecular</u><u> compound X is 16.55g/mol</u>

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