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a_sh-v [17]
2 years ago
5

The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers.

Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
3 0

Answer:

See explanation

Explanation:

We can describe electrons using four sets of quantum numbers;

principal quantum number (n)

orbital quantum number (l)

magnetic quantum number (ml)

spin quantum number (ms)

Since no two electrons in an atom can have the same value for all four quantum numbers according to Pauli exclusion theory, for the orbitals given one possible value for each quantum number is shown below;

For 1s-

n = 1, l= 0, ml = 0, ms= 1/2

For 2s-

n= 2, l =0, ml=0, ms=1/2

For 1s and 2s orbitals, there is only one possible value for ml which is zero.

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Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)
Dovator [93]

Answer:

1. 0.97 V

2. Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)

Explanation:

In this case, we can start with the <u>half-reactions</u>:

Ag^+~_(_a_q_)->~Ag_(_s_)

Al_(_s_)~->~Al^+^3~_(_a_q_)

With this in mind we can <u>add the electrons</u>:

Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)  <u>Reduction</u>

Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~ <u>Oxidation</u>

The reduction potential values for each half-reaction are:

Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_) - 0.69 V

Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_) -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:

Al_(_s_)~->~Al^+^3~+~2e^-~ +1.66 V

Finally, to calculate the overall potential we have to <u>add</u> the two values:

1.66 V - 0.69 V = <u>0.97 V</u>

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)

I hope it helps!

3 0
3 years ago
What ions are released when water is mixed with a base?​
ZanzabumX [31]

Answer:

When dissolved in water, acids donate hydrogen ions (H+). Hydrogen ions are hydrogen atoms that have lost an electron and now have just a proton, giving them a positive electrical charge. Bases, on the other hand, mixed with water yield hydroxide ions (OH-).

5 0
2 years ago
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Nastasia [14]

i believe the answer is success of a policy. if this was correct please mark brainliest and lmk if you have any more questions x

3 0
3 years ago
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Answer:

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Explanation:

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6 0
2 years ago
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N2__+3H2= 2NH3
ch4aika [34]
Use the molar mass of ammonia to change the grams to moles and then use mole-mole ratio

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