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snow_tiger [21]
3 years ago
12

What element in magma is most abundant

Chemistry
2 answers:
zheka24 [161]3 years ago
7 0

Answer:

Oxygen and Silicon

Explanation:

Oxygen and Silicon are the most abundant elements in magma, SiO₂

<u>-TheUnknownScientist</u>

pishuonlain [190]3 years ago
6 0
Oxygen :) hope it helped
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A 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O. Find the mass of sulfur in a sample of CaSO4 with a m
andrey2020 [161]

The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

<h3>How to calculate mass of an element in a compound?</h3>

According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.

This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g

Next, we calculate the percent ratio of each element in the compound; CaSO4.

  • Ca = 3.06g/10.4g × 100 = 29.42%
  • S = 2.45g/10.4g × 100 = 23.56%
  • O = 4.89g/10.4g × 100 = 47.02%

According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:

  • Ca = 29.42/100 × 65.8g = 19.36g
  • S = 23.56/100 × 65.8g = 15.50g
  • O = 47.02/100 × 65.8g = 30.94g

Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

Learn more about mass at: brainly.com/question/13672279

#SPJ1

5 0
1 year ago
Why is it important for scientists to replicate each other's experiments
EastWind [94]
A. Scientific results presented by a scientist should be reproducible anywhere in the world, without this, the results can not be accepted as theory.
6 0
3 years ago
Read 2 more answers
A plant would not be able to complete photosynthesis without
Alenkasestr [34]

Answer:

Glucose

Explanation:

It's the food plants need to complete photosynthesis.

5 0
3 years ago
Read 2 more answers
1.
garik1379 [7]

Explanation:

1.

Given parameters:

Frequency of the radiation  = 8.4 x 10¹⁴Hz

Unknown:

Energy of the wave  = ?

Solution:

The energy of a wave is given by the expression below;

    E  = hf

E is the energy

h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

f is the frequency

 Now insert the parameters and solve;

 E  =  6.63 x 10⁻³⁴m²kg/s x 8.4 x 10¹⁴Hz

 E  = 5.57 x 10¹ x 10⁻²⁰J

 E  = 5.57 x 10⁻¹⁹J

   

2.

Given parameters:

Wavelength = 2.13 x 10⁻¹³m

Unknown:

Frequency of the wave = ?

Solution:

The frequency of a wave can be determined using the expression;

     C  = f∧

C is the speed of light = 3 x 10⁸m/s

f  is the frequency

∧ is the wavelength

      f  = \frac{C}{wavelength}   = \frac{3  x 10^{8} }{2.13 x 10^{-13} }   = 1.41 x 10²¹hz

5 0
3 years ago
A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and
Dmitry_Shevchenko [17]

Answer:

1. Rate =k [NO]^{2}[Cl_{2}]

2. k= 0.42 \frac{L^{2}}{mol^{2}*s}

Explanation:

Rate =k [NO]^{m}[Cl_{2}]^{n}

Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2

Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1

Rate =k [NO]^{2}[Cl_{2}]^{1}

Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12}  = 0.42 \frac{L^{2}}{mol^{2}*s}

6 0
2 years ago
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