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Nookie1986 [14]
3 years ago
15

When the nuclide iron-59 undergoes beta decay: The name of the product nuclide is . The symbol for the product nuclide is .

Chemistry
1 answer:
Travka [436]3 years ago
5 0

Answer:

Explanation:

⁵⁹₂₆Fe --------- ⁰₋₁e + ⁵⁹₂₇Co

Co- 59 is known as Cobalt

its symbol is ⁵⁹₂₇Co

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What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
Which of the following is a physical change?
vodka [1.7K]
Hello,
A physical change describes a change that does physically and does not display “chemical” signs which are signs that indicate a precipitate being formed, change in color, density, or producing gas, etc. “Tearing a piece of paper in half” is a physical change because like I said earlier it doesn’t show any chemical change signs. I hope this helps you out!
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The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the
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4.1 h = 14760 s 

<span>t 1/2 = ln 2 / k </span>

<span>k = rate reaction = 4.97 x 10^-5 </span>

<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>

<span>2.08 = 4.97 x 10^-5 t </span>

<span>t = 41839.9 s = 11 h 37 min 19 s</span>
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3 years ago
PLEASE ANSWER THIS QUESTION ASAP.
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Equal is the answer

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The answer to the question is a.

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