One way to identify the type of radioactive decay produced in a reaction is to pass the emission through an electric field. Desc
1 answer:
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Answer:
0.0933 moles/Litre
Explanation:
We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:
Energy cost =
Given that:
Energy = 100 W for 60 minutes
100 W = 100 J/s
= 100 J/s × (60 × 60) seconds
= 3.6 × 10⁵ J
Let now convert 3.6 × 10⁵ J to eV; we have:
= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV
= 2.247 × 10²⁴ eV
So, number of N-atom used up to form compounds will now be:
= 2.247 × 10²⁴ eV ×
= 1.123 × 10²³ N-atom
To moles; we have:
=
= 0.186 moles
However, we are expected to leave our answer in concentration (i.e in moles/L)
since we are given 2L
So; 0.186 moles ⇒
= 0.0933 moles/Litre
Answer:
a) The theoretical yield is 408.45g of
b) Percent yield =
Explanation:
1. First determine the numer of moles of and
.
Molarity is expressed as:
M=
- For the
M=
Therefore there are 1.75 moles of
- For the
M=}{1Lsolution}[/tex]
Therefore there are 2.0 moles of
2. Write the balanced chemical equation for the synthesis of the barium white pigment, :
3. Determine the limiting reagent.
To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:
- For the :
- For the :
As the is the smalles quantity, this is the limiting reagent.
4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.
5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:
Percent yield =
Percent yield =
The real yield is the quantity of barium white pigment you obtained in the laboratory.