Answer:
B
Explanation:
Shows actual sacrifice in order to train and be the best.
Answer:
7C7H6O3 + 8C4H6O3 = 9C9H8O4·H2O
Explanation:
The periodic table contains the pure substances
Answer:
Q = 2640.96 J
Explanation:
Given data:
Mass of He gas = 10.7 g
Initial temperature = 22.1°C
Final temperature = 39.4°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 39.4°C - 22.1°C
ΔT = 17.3°C
Q = 10.7 g× 14.267 J/g.°C × 17.3°C
Q = 2640.96 J
The friction aids in grasping and walking. The friction ridge skin also contains numerous sweat glands, and the pore openings are located along the tops of the ridges. The friction ridge skin does not contain sebaceous (oil) glands or hair follicles.