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trasher [3.6K]
2 years ago
9

A Hydrocarbon C₄H₁₀ has a boiling point of 0, another hydrocarbon C₆H₁₄ has a boiling point of 69. What would you expect the boi

ling point of C₈H₁₈ to be?
Chemistry
2 answers:
cupoosta [38]2 years ago
5 0
If the trend is linear, that is boiling point increases by a constant amount for each additional saturated carbon, the boiling point of octane would be 69*2 because you are adding two saturated carbons. So the predicted boiling point is 138C, which is very close to the literature value
katen-ka-za [31]2 years ago
3 0
Pretty sure it would be at 138 
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Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{P_2}=\frac{T_1}{T_2}

where,

P_1 = initial pressure = 1.10 atm

P_2 = final pressure = ?

T_1 = initial temperature = 28.0^oC=273+28.0=301.0K

T_2 = initial temperature = -2.00^oC=273+(-2.00)=271.0K

Now put all the given values in the above equation, we get:

\frac{1.10atm}{P_2}=\frac{301.0K}{271.0K}

P_2=0.990atm

Thus, the final pressure of the basketball is, 0.990 atm

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mel-nik [20]

Answer:

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