The answer is A. Hope this helps!!!
Sorry if I'm wrong but I think that it is B.
Answer:
The equation is H2SO4 + 2KOH ===> K2SO4 + 2H2O
The molarity of base is 0.257 M
Explanation:
Using titration equation CAVA/CBVB = NA/NB
Where NA is the number ov mole of acid =1
Using titration equation
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1
NB is the number of mole of base = 2
CA is the molarity of acid =1.5M
CB is the molarity of base = to be calculated
VA is the volume of acid = 13.7 mL
VB is the volume of base = 80 mL
Substituting
1.5×80/CB×13.7 = 1/2
Therefore CB = 1.5×13.7×2/80×1
CB = 0.257 M.
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.
molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃
Then, divide the given amount of substance by the calculated molar mass.
number of moles = (20 g)(1 mol of CaCO₃/100 g)
number of moles = 0.2 moles of CaCO₃
<em>Answer: 0.2 moles</em>
