1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):
3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24
Good luck!
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
The density is 1.2g/mL<span />
Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol
The answer is 43 L if I am correct.
