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Sladkaya [172]
4 years ago
13

Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?

Physics
1 answer:
Assoli18 [71]4 years ago
6 0

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion s=ut+\frac{1}{2}at^2

40=0\times 10+\frac{1}{2}a10^2

a=0.8944m/sec^2

Now from first equation of motion v=u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So v=u+at=0+0.8944\times 10=8.944m/sec

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A ball is thrown upward with a speed of 40 m/s. Approximately how much time goes it take the ball to travel from the release loc
yulyashka [42]

Answer:

(I). The time at highest point 4.0 sec.

(II).  It returns to back to its original height in 8.1 sec

Explanation:

Given that,

Velocity v=40\ m/s

(I). We need to calculate the time at highest point

Using equation of motion

v=u+gt

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

Put the value into the formula

0=40-9.8t

-40=-9.8t

t=\dfrac{40}{9.8}

t=4.0\ sec

(II). We know that, when the ball to travel from the initial point and reached at initial point then the displacement is zero.

We need to calculate the total time when it returns to back to its original height

Using equation of motion

s=ut-\dfrac{1}{2}gt^2

Where, s = displacement

g = acceleration due to gravity

t = time

u = velocity

Put the value in the equation

0=40t-\dfrac{1}{2}9.8t^2

80t-9.8t^2=0

t=0, 8.1 sec

Hence. (I). The time at highest point 4.0 sec.

(II). It returns to back to its original height in 8.1 sec

5 0
3 years ago
On an icy road, a 1100 kg car moving at 55 km/h strikes a 480 kg truck moving in the same direction at 37 km/h . The pair is soo
statuscvo [17]

Answer:

Speed of the wreckage = 49.29 km/hr

Explanation:

This question is solved simply by using the conservation of momentum law.

The momentum of the three moving bodies are calculated below:

Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr

Momentum of Truck : 480 * 37 = 17760 kg.km/hr

Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr

Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg

The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:

Final Momentum = Initial Momentum

Final Velocity * Total mass = Momentum of all three vehicles combined

Final Velocity * 2880 = 60500 + 17760 + 63700

Final Velocity = 49.29 km/hr

7 0
4 years ago
Read 2 more answers
Topics related to physics​
Bezzdna [24]

Answer:

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Kinematics

Dynamics

Light

Sound

7 0
2 years ago
A 20.94 g sample of an unknown metal is heated to 99.4 oC in a hot water bath. The metal sample is transferred to a calorimeter
MAXImum [283]

Answer:

1092 J

Explanation:

From the question,

Assuming no heat is lost to the surrounding

Heat lost by the metal = Heat gained by water.

H' = Cm(t₂-t₁)................. Equation 1

Where H' = Heat lost by the metal, C = specific heat capacity of water,  m = mass of water, t₂ = Final temperature of the mixture, t₁ = Initial temperature of water

But,

m = D'v................... Equation 2

Where D' = Density of water, v = volume of water.

Given: D' = 1000 kg/m³, v = 100 mL = 100/1000000 = 0.0001 m²

Substitute into equation 2

m = 1000(0.0001)

m = 0.1 kg.

Also given: C = 4200 J/kg.°C, t₁ = 22 °C, 24.6 °C

Substitute into equation 1

H' = 4200×0.1×(24.6-22)

H' = 420(2.6)

H' = 1092 J.

Hence the heat (q) lost by the metal = 1092 J

3 0
4 years ago
True or False. The two metals in a battery are the electrolytes.<br> True<br> False
liubo4ka [24]
Falseeeeeeeeeeeeeeeeeeeeeeeeeeeee
6 0
3 years ago
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