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soldi70 [24.7K]

2 years ago

7

.89m/s A vehicle that starts to move from the rest gets an acceleration of 5m/s² within 2 seconds. Calculate the velocity and di

stance covered by the vehicle within the given time. [Ans: 10m/s, 10m]

1 answer:

GuDViN [60]2 years ago

5 0

<u>Explanation:</u>

s = ? u = 0m/s v = ? a = 5m/s² t = 2s

v = u + at

= 0 + (5 x 2)

= 10 m/s

s = ut + 1/2 at²

= (0)(2) + x $\frac{1}{2}$ x 5 x 2²

= 10 m

Hope this helps!

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An Olympic swimmer swims 50.0 meters in 23.1 seconds . What is his average speed

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Light of wavelength 425.0 nm in air falls at normal incidence on an oil film that is 850.0 nm thick. The oil is floating on a wa

creativ13 [48]

Answer:

in oil film λ = 303.57 10⁻⁹ m

in the water film λ = 319.55 10⁻⁹ m

Explanation:

When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,

when light reaches a surface it has a mass much greater than the mass of the photons (m = 0), therefore there is an elastic collision where the frequency does not change, due to the speed of light in the material medium changes, therefore the only possibility is that the wavelength in the material changes, to maintain the relationship

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n = λ₀ /λ

λ = λ₀ / n

let's calculate

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those wavelengths are in the ultraviolet

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3 years ago

How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$

With the following condition :

W = work (J)
F = force (N)
s = shift or displacement (m)

Now, the s (displacement) can be written as ∆h (altitude change) because the object move to vertical line. The formula can also be changed to:

$\boxed{\sf{\bold{W = F \times \Delta h}}}$

With the following condition :

W = work (J)
F = force (N)
$\sf{\Delta h}$ = change of altitude (m)

If an object has mass, then the object will also be affected by gravity. Always remember that F = m × g. So that :

$\sf{W = F \times \Delta h}$

$\boxed{\sf{\bold{W = m \times g \times \Delta h}}}$

With the following condition :

W = work (J)
m = mass of the object (kg)
g = acceleration of the gravity (m/s²)
$\sf{\Delta h}$ = change of altitude (m)

<h3>Problem Solving</h3>

We know that :

F = force = 100 N
$\sf{\Delta h}$ = change of altitude 300 m

What was asked :

W = work = ... J

Step by step :

$\sf{W = F \times \Delta h}$

$\sf{W = 100 \times 300}$

$\boxed{\sf{W = 30,000 \: J = 30 \: kJ}}$

<h3>Conclusion</h3>

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

<h3>See More :</h3>

Work that he had done to lift object brainly.com/question/26341717
Converting work to potential energy brainly.com/question/26487284

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