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WARRIOR [948]
3 years ago
6

Pls I need it fast , its for my homework and I can’t find it

Physics
1 answer:
frez [133]3 years ago
5 0

Answer:

first one is  series second one is paralle

Explanation:

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HELP PLS 100 POINTS TAKING TEST RN
s2008m [1.1K]

Answer:

I think he answer is C but I could be wrong

Explanation:

brainliest plz

8 0
3 years ago
Read 2 more answers
A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 2
Alinara [238K]

Answer:

923.44N

Explanation:

Obviously Fn cannot equal Fg since the elevator is moving up  

Where Fn is the force read on the scale

Fg is gravitational force=mg=77.6 x 9.8=760.48N

So we use this equation:  

Fnet = Fn - Fg  

ma = Fn - mg

77.6 x 2.1 = Fn – 760.48

162.96N = Fn – 760.48N  

923.44 N = Fn

The answer is 923.44 N

6 0
3 years ago
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According to perception of movement, in order to sense movement, humans need to see an object _____.
lesya692 [45]

Answer: The correct answer for the blank is- a. change its position relative to other objects.

Perception of motion can be described as a phenomenon of inferring the  direction and speed and of objects, which are moving in a visual scene.

An object is said to be in motion if its position is changed with respect to objects that are present in its surrounding.

Thus, in order to sense motion of objects, humans beings are required to see an object change its position with respect to other objects.

8 0
3 years ago
A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
What is the following correct way to write 2,330,000 In a scientific notation
NISA [10]

Answer:

2.33 × 10^6

hope this helps.

8 0
3 years ago
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