Ask question

Ask question

All categories

3 years ago

6

Pls I need it fast , its for my homework and I can’t find it

1 answer:

frez [133]3 years ago

5 0

Answer:

first one is series second one is paralle

Explanation:

You might be interested in

How much work done if an object is moving to the right and a force of 75. 0n is applied at 125 degrees to the motion while the o

bogdanovich [222]

Answer:

-322.64 J

Explanation:

75 N * cos 125 * 7.5 = -322.64 J

4 0

2 years ago

A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete

Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is $6.25\times 10^{- 3} ft/s^{2}$

Solution:

As per the question:

Constant velocity of the horse in the horizontal, $v_{x} = 1 ft/s$

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

$20^{2} + 10^{2} = l^{2}$

$l^{2}= 500$

Now,

$x^{2} + y^{2} = 500$ (1)

Differentiating equation (1) w.r.t 't':

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$

$x\frac{dx}{dt} = - y\frac{dy}{dt}$

where

$\frac{dx}{dt}$ = Rate of change of displacement along the horizontal

$\frac{dy}{dt}$ = Rate of change of displacement along the vertical

$v_{x}$ = velocity along the x-axis.

$v_{y}$ = velocity along the y-axis

$xv_{x} = -yv_{y}$

$v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s$

$|v_{y}| = 0.5\ ft/s$

Acceleration of the hay bale is given by the kinematic equation:

$v_{y}^{2} = u_{y} + 2ay$

$(-0.5)^{2} =0 + 2ay$

$0.25 = 2ay$

$\frac{0.25}{2y} = a$

$a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}$

7 0

3 years ago

How can I make the atomic model of boron?

zloy xaker [14]

This should help

there always needs to be 2 electrons in the first shell then 8 electrons in each shell and continue till you not have any more number of electron left

8 0

3 years ago

Which is an example of observational learning?

vekshin1

Janice is the one who learned something by watching what was going on in the world around her.

8 0

2 years ago

Read 2 more answers

Why is the contribution of the wavelets lying on the back of secondary wave front zero?

Tresset [83]

Answer:

The contribution of the wavelets lying on the back of the wave front is zero because of something known as the Obliquity Factor. It is assumed that the amplitude of the secondary wavelets is not independent of the direction of propagation, Sources: byju's.com

3 0

1 year ago

Read 2 more answers