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Olegator [25]
3 years ago
14

A dog sits 1.5 m from the center of a merry-go-round. The merry-go-round is set in motion, and the dog's tangential speed is 1.5

m/s. What is the dog's centripetalacceleration?
Physics
1 answer:
natka813 [3]3 years ago
3 0
<h2>Dog's centripetal acceleration is 1.5 m/s²</h2>

Explanation:

Centripetal acceleration is given by

                    a=\frac{v^2}{r}

Where v is the tangential velocity and r is the radius.

         Here

        Tangential velocity, v = 1.5 m/s

        Radius, r = 1.5 m

Substituting

        a=\frac{v^2}{r}\\\\a=\frac{1.5^2}{1.5}\\\\a=1.5m/s^2

Dog's centripetal acceleration is 1.5 m/s²

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