Question

A dog sits 1.5 m from the center of a merry-go-round. The merry-go-round is set in motion, and the dog's tangential speed is 1.5 m/s. What is the dog's centripetalacceleration?

Answer 1

Dog's centripetal acceleration is 1.5 m/s²

Explanation:

Centripetal acceleration is given by

                    $a=\frac{v^2}{r}$

Where v is the tangential velocity and r is the radius.

         Here

        Tangential velocity, v = 1.5 m/s

        Radius, r = 1.5 m

Substituting

        $a=\frac{v^2}{r}\\\\a=\frac{1.5^2}{1.5}\\\\a=1.5m/s^2$

Dog's centripetal acceleration is 1.5 m/s²