Explanation:
First, we will calculate the number of moles of HF as follows.
No. of moles of HF = volume × concentration of HF
=
= 1.78 mol
According to Henderson-Hasselbalch equation,
pH =
=
Since, no change in the volume is taking place. Hence, putting the given values into the above formula as follows.
pH =
= 0.208
= 1.614
moles of NaF = 2.87 mol
Thus, we can conclude that moles of solid NaF present are 2.87 mol.
Answer:
-85 °C
Explanation:
O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.
H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter
molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.
I'm not 100% sure but I'm leaning towards D. :)
Average velocity (v) of an object is equal to its final velocity (v) plus initial velocity (u), divided by two. Where: ¯v = average velocity.
Hope this helps :)
And could i please have brainliest