Answer : The cell potential for this reaction is 0.50 V
Explanation :
The given cell reactions is:

The half-cell reactions are:
Oxidation half reaction (anode): 
Reduction half reaction (cathode): 
First we have to calculate the cell potential for this reaction.
Using Nernest equation :
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B2.303RT%7D%7BnF%7D%5Clog%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BPb%5E%7B2%2B%7D%5D%7D)
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature = 
n = number of electrons in oxidation-reduction reaction = 2
= standard electrode potential of the cell = +0.63 V
= cell potential for the reaction = ?
= 3.5 M
= 
Now put all the given values in the above equation, we get:


Therefore, the cell potential for this reaction is 0.50 V
Umm...Well...
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Answer:
moving i think! Hope this helps
Explanation:
Answer:
3.064 $
Solution:
First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,
1 Kilogram = 2.20462 Pounds
Hence, as given,
1 Pound of Margarine costs = 1.39 Dollars
So,
2.20462 Pounds Margarine will cost = X Dollars
Solving for X,
X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound
X = 3.064 Dollars