Answer:
The answer is 2.107 × 10²⁴ He atoms
Explanation:
To find the number of atoms given the number moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
N = 3.5 × 6.02 × 10²³
We have the final answer as
<h3>2.107 × 10²⁴ He atoms</h3>
Hope this helps you
Answer:
Based on these values and on consideration of molecular geometry, the H-Se bond can be considered almost _____non-polar___ and the molecule is __polar_____.
Explanation:
Looking at the difference in electro negativity of the two elements; hydrogen and selenium, one may be led to the conclusion that the molecule is nonpolar since the magnitude of electronegative between the two bonding atoms is minimal.
However, electro negativity difference alone is insufficient to determine the polarity of a molecule. The structure of the molecule is also considered. Based on the structure of the molecule, it is expected to have a dipole moment. Hence the molecule is polar.
The reaction of removing CO2
using LiOH is the following:
2 LiOH + CO2 -----> Li2CO3
+ H2O
By solving the amount of CO2
the LiOH can scrub:
(3.50 × 10^4 g LiOH) (1 mol LiOH/
24 g LiOH) ( 1 mol CO2 / 2 mol LiOH) ( 44 g CO2 /1 mol CO2) = 32, 083.33 g CO2
it can scrub
<span>Since number of astronaut = 32,
083.33 g / 9 (8.8 × 10^2) = 4 astronaut</span>
Answer:
<u>Yes</u>
Explanation:
Remember, <u>Newton's third law of motion;</u> which says in part that <em>"Every action has an equal and opposite reaction."</em>
Hence, in this case, the fact that the doorbell rang out implies that there was another force that was exerted on it; which is, John's finger pressing the doorbell.
In other words, when John uses his fingers to press the doorbell button he applies a force (a mechanical force), and that force results in an opposite reaction; the ringing of the doorbell.
If you don't practice enough it's obviously going to be hard but if you practice enough it's going to be a piece of cake so don't think if it's going to be hard or not just think it's going to be worth the try at the very end
