Answer:
27.19 cm.
Explanation:
From the question given above, the following data were obtained:
Height (h) of cylinder = 6461.76 cm
Volume (V) of cylinder = 15000000 cm³
P1 (π) = 3.14
Radius (r) =.?
Thus, we can obtain the radius of the cylinder water tank by using the following formula as illustrated below:
V = πr²h
15000000 = 3.14 × r² × 6461.76
15000000 = 3.14 × 6461.76 × r²
Divide both side by 3.14 × 6461.76
r² = 15000000 / (3.14 × 6461.76)
Take the square root of both side
r = √[15000000 / (3.14 × 6461.76)]
r = 27.19 cm
Thus, the radius of the cylinder water tank is 27.19 cm.
Answer : The mass of potassium phosphate needed will be 3.98 grams.
Explanation : Given,
Molarity of potassium phosphate = 0.75 M = 0.75 mole/L
Molar mass of potassium phosphate = 212.27 g/mole
Volume of solution = 25.0 mL = 0.025 L (conversion used : 1 L = 1000 mL)
Molarity : It is defined as the number of moles of solute present in one liter of solution.
In this problem solute is, potassium phosphate.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the mass of potassium phosphate needed will be 3.98 grams.
Answer:
A substance that can not be separated into any kinds of matter
Explanation:
The hydroxide ion concentration [OH-] in an aqueous solution is 6.66 x 10⁻⁹ M
Experimental measurements of the pKw of water at 25ºC yielded a result of 14.0. The same method used to determine the pKa of all other water-soluble compounds that can function as acids in aqueous solution can also be used to determine this value from the examination of thermodynamic or electrochemical data for these aqueous solutions.
Water has a pkw=14
So it can be represented as,
[H+] [OH-] = 1×10^-14
Given [H+] = 1. 5×10^−6
So, [OH-] = (1*10^-14) / ( 1.5*10^-6)
= 6.66 x 10⁻⁹ M
To know more about Aqueous Solution refer:
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