2 scoops for 1 sunday
so 18/2
9 sundaes
Answer:
The area of rhombus PQRS is 120 m.
Step-by-step explanation:
Consider the rhombus PQRS.
All the sides of a rhombus are equal.
Hence, PQ = QR = RS = SP = 13 m
The diagonals PR and QS bisect each other.
Let the point at of intersection of the two diagonals be denoted by <em>X</em>.
Consider the triangle QXR.
QR = 13 m
XR = 12 m
The triangle QXR is a right angled triangle.
Using the Pythagorean theorem compute the length of QX as follows:
QR² = XR² + QX²
QX² = QR² - XR²
= 13² - 12²
= 25
QX = √25
= 5 m
The measure of the two diagonals are:
PR = 2 × XR = 2 × 12 = 24 m
QS = 2 × QX = 2 × 5 = 10 m
The area of a rhombus is:

Compute the area of rhombus PQRS as follows:


Thus, the area of rhombus PQRS is 120 m.
6x6x6=216
Six multiply six equal 36 and multiply it again by six it will be 216
Answer:
(3, -4)
Step-by-step explanation:
The correct equation is:

From the list of given points, we have to identify which point lies on the graph. This can be done by using the value of x-coordinates from the given points and see if they result in the corresponding y-coordinate:
For point (1, 4)
, This is not equal to 4, so it does not lie on the graph of given function.
For point (3, -4)
, The answer ans corresponding y-coordinate are the same. This means, (3, -4) point lies on the graph of given function.
Likewise, checking for 3rd and 4th point we find out that they do not lie on the graph.
So the correct answer is (3, -4)