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krok68 [10]
3 years ago
11

What direction are the groups (families) in the periodic table?

Chemistry
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

left

Explanation:

Troyanec [42]3 years ago
6 0
The answer to the question is left
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A hydrogen atom in an excited state can be ionized with less energy than when it is in its ground state. What is n for a hydroge
Molodets [167]

Explanation:

It is known that formula for the ionization energy of hydrogen atom is as follows.

               E = \frac{13.6 eV}{n^{2}}

or,          n = \sqrt{\frac{13.6}{E}}

The value of energy is given as 0.544 eV. Therefore, we will calculate the value of n as follows.

                   n = \sqrt{\frac{13.6}{E}}

                      = \sqrt{\frac{13.6}{0.544 eV}}

                      = 5

Thus, we can conclude that n equals to 5 for a hydrogen atom if 0.544 eV of energy can ionize it.

5 0
3 years ago
What are the transition metals
Valentin [98]
Theyre the big bunched up group in the middle of the periodic table
8 0
3 years ago
Read 2 more answers
Increasing temperature makes a
LenKa [72]

Answer:

High temperature increases the number of high energy collisions

Explanation:

Increasing the temperature a reaction takes place at increases the rate of reaction. At higher temperatures, particles can collide more often and with more energy, which makes the reaction take place more quickly.

5 0
3 years ago
3. Use the chart to answer the following question. Amanda found a stone
REY [17]

Answer:

Quartz

Explanation:

6 0
3 years ago
Eading and
4vir4ik [10]

Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles

The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

Mass of Cl_2= moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g

Thus 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

5 0
3 years ago
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