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Natasha_Volkova [10]
3 years ago
6

HELP ASAP!

Chemistry
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

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Explanation:

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Why does bromine not react with sulphur?​
Zielflug [23.3K]

Answer:

The thermodynamic parameter which is of significance in this case is the 'Reduction Potential' for molecular bromine which is ~ +1.1 v vs N.H.E. In other words, it is a strong oxidizing agent. The bromine will oxidize sulfur compounds in which the valence of sulfur is lower than six to sulfate.

There are many possible reactions. Here is one possible example:

Na2 S2O3 + 4Br2 + 5 H2O = 2NaHSO4 + 8 HBr

8 0
3 years ago
Read 2 more answers
Can methene exist? Explain yes or no
finlep [7]
Methene (non existent) would be an alkene and therefore would need a carbon to carbon double bond, since it only has one carbon it can't bond to another, this is why the lowest alkene is ethene (C2H4).         i hope this helps  
7 0
3 years ago
The following steps are unbalanced half-reactions involved in the nitrogen cycle. Balance each half-reaction to show the number
Vadim26 [7]

This is an oxidation reaction. The balanced equation is as follows:

      6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Rules to balance redox reaction in acidic medium

  1. Write the given equation in ionic form
  2. Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
  3. Break the equation into two halfs
  4. Balance the half equations

A. Balance all other atoms except Oxygen and hydrogen

B. Balance oxygen by adding H2O to the side deficient in oxygen

C. Balance hydrogen by adding H+ ions

D. Balance charge by adding electrons

5. Add the two half such that electrons gets cancelled

Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.

              N₂(g) → NO₃⁻(aq)

  • balance N.

           N₂ → 2NO₃⁻

  • balance O by adding H2O

          6H₂O  + N₂ → 2NO₃⁻

  • Now balance Hydrogen

            6H₂O  + N₂ → 2NO₃⁻+ 12H⁺

  • balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.

             6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.

learn more about balancing redox reactions at brainly.com/question/10203480

#SPJ4

3 0
1 year ago
HELP: MODELING MOLECULES!!!!!!!!!!!!!!!!
garik1379 [7]
<span>Sulfur Hexachloride SCl6 So now we count the number of valence electrons each has by seeing what column it's in, (1-8) not counting the columns of the transition metals. Since Sulfur is in the 6th and Chlorine is in the 7th, and there are 6 chlorines, we can add up all their valence electrons: 6*1+7*6=48 valence electrons. But remember that electrons come in pairs, either in bonds or as lone pairs. So I usually divide the valence electron number by 2 and just think about placing pairs. It's up to you, but I think it's convenient since we can count "1" in our mind each time we place a bond or a electron pair. So we need to place 24 pairs/bonds. So we can guess that sulfur is a central atom and draw out a bond from sulfur to each chlorine. Since Sulfur is in the 3rd row it can use d-orbitals to break the octet rule. So when we bond all the chlorines onto sulfur we get:
(see the figure)

and 
</span><span>So we made 6 bonds, that means we used up 12 electrons, so if you're counting (AND YOU SHOULD BE!) you have 36 electrons or simply 18 electron pairs left to place. Now let's give chlorine a neutral charge.</span>

8 0
3 years ago
A compound has the empirical formula CH2O. If its molar mass is 150 g/mol, what is the molecular formula of the compound?
IgorLugansk [536]

Answer:

C5H10O5

Explanation:

The molecular formula is a multiple of the empirical formula. I.e

Molecular formula => [CH2O]n

[CH2O]n = 150

[12 + (2x1) + 16 ]n = 150

30n = 150

Divide both side by the coefficient of n i.e 30

n = 150/30 = 5

Molecular formula => [CH2O]n

Molecular formula => [CH2O]5

Molecular formula => C5H10O5

8 0
3 years ago
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