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Natasha_Volkova [10]
2 years ago
6

HELP ASAP!

Chemistry
1 answer:
Jet001 [13]2 years ago
3 0

Answer:

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Explanation:

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Use the periodic table to identify the molar mass of each element below. Answer without doing any calculations.
Delicious77 [7]

Answer:

Beryllium (Be) : 9.01 g/mol

Silicon (Si) : 28.09 g/mol

Calcium (Ca) : 40.08 g/mol

Rhodium (Rh) : 102.91 g/mol

Explanation:

8 0
3 years ago
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If the heat of reaction is negative, that means that:
Crazy boy [7]

Answer:

if the heat of reaction is positive, the reaction is said to be endothermic; if negative, exothermic.

Explanation:

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4 0
2 years ago
Can someone help me with this
Trava [24]

Answer:

I think cold front if not than its c

7 0
2 years ago
What is the molarity of a solution that contains 0.702 mol KCl in 0.98 L solution?
Lubov Fominskaja [6]

Answer:

C. 0.72 M

Explanation:

To calculate the molarity use the following equation, C=n/V

You have the molar number n which is 0.702 and the volume 0.98 L

Replace those numbers in the formula C=0.702/0.98= 0.72 M

6 0
2 years ago
How many moles are contained 80.3 gram of sm(no3)3
swat32
<h3>Answer:</h3>

0.239 mol Sm(NO₃)₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 80.3 g Sm(NO₃)₃

[Solve] moles Sm(NO₃)₃

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Sm - 150.36 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                 \displaystyle 80.3 \ g \ Sm(NO_3)_3(\frac{1  \ mol \ Sm(NO_3)_3}{336.39 \ g \ Sm(NO_3)_3})
  2. [DA] Divide [Cancel out units]:                                                                        \displaystyle 0.238711 \ mol \ Sm(NO_3)_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃

3 0
2 years ago
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