Answer:
Beryllium (Be) : 9.01 g/mol
Silicon (Si) : 28.09 g/mol
Calcium (Ca) : 40.08 g/mol
Rhodium (Rh) : 102.91 g/mol
Explanation:
Answer:
if the heat of reaction is positive, the reaction is said to be endothermic; if negative, exothermic.
Explanation:
hope this helps
i am so sorry if this is the wrong answer
Answer:
I think cold front if not than its c
Answer:
C. 0.72 M
Explanation:
To calculate the molarity use the following equation, C=n/V
You have the molar number n which is 0.702 and the volume 0.98 L
Replace those numbers in the formula C=0.702/0.98= 0.72 M
<h3>
Answer:</h3>
0.239 mol Sm(NO₃)₃
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 80.3 g Sm(NO₃)₃
[Solve] moles Sm(NO₃)₃
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Sm - 150.36 g/mol
[PT] Molar Mass of N - 14.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃