Find the buoyant force of a rectangular solid of the given dimensions submerged in water so that the top side is parallel to the
surface of the water. The buoyant force is the difference between the fluid forces on the top and bottom of the solid
1 answer:
Answer:
Here is the continuation to the question ; The buoyant force is the difference between the fluid forces on the top and bottom of the solid. (The weight-density of water is 62.4 pounds per cubic foot.)
Hence, bouyant force is calculated as = 11980.8lb
Step-by-step explanation:
The steps are as shown in the attachment.
You might be interested in
Answer:
9 units²
Step-by-step explanation:
calculate the area of Δ ABC as
area of rectangle - area of 3 outer right triangles
area of rectangle = 5 × 4 = 20 units²
area of left Δ = × 3 × 3 = 4
units²
area of Δ on right = × 2 × 4 = 4 units²
area of top Δ = × 5 × 1 = 2
units²
Then
area of Δ ABC = 20 - 4 - 4 - 2
= 20 - 11 = 9 units²