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JulsSmile [24]
3 years ago
7

Find the buoyant force of a rectangular solid of the given dimensions submerged in water so that the top side is parallel to the

surface of the water. The buoyant force is the difference between the fluid forces on the top and bottom of the solid

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

Here is the continuation to the question ; The buoyant force is the difference between the fluid forces on the top and bottom of the solid. (The weight-density of water is 62.4 pounds per cubic foot.)

Hence, bouyant force is calculated as = 11980.8lb

Step-by-step explanation:

The steps are as shown in the attachment.

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Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar      R

5.8        0.42

6.1         0.38

16.02    0.08

15.95    0.15

16.12     0.42

6.18      0.23

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16.2      0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

LCL=10.9361

8 0
3 years ago
√4/9 =? <br><br>I need help finding the missing number.
kotykmax [81]

√4 / 9  

√4 = 2

So the answer would be....

2 / 9

Hope this helps!

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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