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Norma-Jean [14]
4 years ago
13

After tasting the salt in the ocean water on a visit to the beach one day, you recall from class that the salt is the __________

in the ocean water.
A. solid
B. solute
C. solution
D. solvent
Physics
2 answers:
GarryVolchara [31]4 years ago
8 0
     The salt of ocean is the solute, because this is within the solvent, which is water.

Letter B 
creativ13 [48]4 years ago
7 0

Answer:B

Explanation:

Water is the solvent so salt is the solute

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Help ASAP
Mashcka [7]

Answer:

The golf ball has a constant velocity

Explanation:

5 0
3 years ago
A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
4 years ago
A free falling object has the velocity time graph shown. What is the objects displacement between 0.0 and 6.0s
zloy xaker [14]

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

d = v_i * t + \frac{1}{2}at^2

here if body starts with zero initial speed then we can say

d = 0 + \frac{1}{2}*9.8*t^2

here we need to find the displacement from t = 0 to t = 6s

so we can say

d = \frac{1}{2}*9.8*6^2

d = 176.4 m

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

6 0
4 years ago
Read 2 more answers
A force of 150 N is continuously applied to an object with a mass of 11 kg over a distance of 2.5 m.The object slides over a sur
Ivahew [28]

Answer:

Final velocity will be 7.31 m/sec

Explanation:

We have given applied force F = 150 N

Mass of the object m = 11 KG

Distance traveled by the object s = 2.5 m

Coefficient of kinetic friction \mu _k=0.3

Acceleration due to gravity g=9.8m/sec^2

So frictional force applied on the object f=-\mu _kmg=-0.3\times 11\times 9.8=-32.34N

So net force = 150-32.34 = 117.66 N

As work done us equal to W=Fs

So work done = 117.66\times 2.5=294.15j

Now according to work energy theorem work done is equal to change in kinetic energy

So \frac{1}{2}mv^2=294.15

\frac{1}{2}\times 11\times v^2=294.15

v =7.31 m/sec

So velocity final velocity will be 7.31 m/sec

4 0
3 years ago
Which one describes how much matter an object contains,using SI units?
GaryK [48]
Mass is how much matter an object contains and it is measured in kilograms, so choice A is correct: 43 kg.
7 0
3 years ago
Read 2 more answers
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