Answer:
He has 5,609,404 J of potential energy
Explanation:
P.E. = M*G*H
65 * 9.8^2 * 8800
Answer:A language is a structured system of communication. Language, in a broader sense, is the method of communication that involves the use of – particularly human – languages. The scientific study of language is called linguistics
Explanation:
This question is incomplete
Complete Question
Three equal point charges are held in place as shown in the figure below
If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.
A) F1=2F2
B) F1=3F2
C) F1=4F2
D) F1=9F2
Answer:
D) F1=9F2
Explanation:
We are told in the question that there are three equal point charges.
q, Q1, Q2 ,
q = Q1 = Q2
From the diagram we see the distance between the points d
q to Q1 = d
Q1 to Q2 = nd
Assuming n = 2
= 2 × d = 2d
Sum of the two distances = d + 2d = 3d
F1 is the force on q due to Q1 and
F2 is the force on q due to Q2,
Since we have 3 equal point charges and a total sum of distance which is 3d
Hence,
F1 = 9F2
Similar:
-
For transverse waves, the waves move in perpendicular direction to the source of vibration.
For longitudinal waves, the waves move in parallel direction to the source of vibration .
They are similar in the sense that energy is transferred in the form of waves.
-
Difference:
-
Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.
Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.
Both momentum and kinetic energy are conserved in elastic collisions (assuming that this collision is perfectly elastic, meaning no net loss in kinetic energy)
To find the final velocity of the second ball you have to use the conversation of momentum:
*i is initial and f is final*
Δpi = Δpf
So the mass and velocity of each of the balls before and after the collision must be equal so
Let one ball be ball 1 and the other be ball 2
m₁ = 0.17kg
v₁i = 0.75 m/s
m₂ = 0.17kg
v₂i = 0.65 m/s
v₂f = 0.5
m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f
Since the mass of the balls are the same we can factor it out and get rid of the numbers below it so....
m(v₁i + v₂i) = m(v₁f + v₂f)
The masses now cancel because we factored them out on both sides so if we divide mass over to another side the value will cancel out so....
v₁i + v₂i = v₁f + v₂f
Now we want the final velocity of the second ball so we need v₂f
so...
(v₁i + v₂i) - v₁f = v₂f
Plug in the numbers now:
(0.75 + 0.65) - 0.5 = v₂f
v₂f = 0.9 m/s
