A Web site that ends in .gov or .edu is probably unreliable. True False
2 answers:
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Answer:
7.65x10^3 m/s
Explanation:
The computation of the satellite's orbital speed is shown below:
Given that
Earth mass, M_e = 5.97 × 10^24 kg
Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg
Orbital radius, r = 6.80 × 10^6m
Based on the above information
the satellite's orbital speed is
V_o = √GM_e ÷ √r
= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6
= 7.65x10^3 m/s
For this case, what we must do is to rewrite these measurements in the same unit in order to compare them.
By writing the measurements in meters we have:
Therefore, physically the correct measure is:
Answer:
the length of a student's textbook most likely is:
30 centimeters