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Eddi Din [679]
3 years ago
6

A group of students are studying how different stimuli affect the growth of plants. They place a growth lamp next to a plant tha

t has been placed in a dark room. To ensure the survival of the plant they make sure to provide an adequate amount of nutrients and water. Which way is the plant most likely to respond?
Chemistry
1 answer:
julsineya [31]3 years ago
4 0

Answer:

grow

Explanation:

it needs light

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O
trasher [3.6K]

Answer: \Delta H^{0} = -879.15 kJ/mol

Explanation: <u>Heats</u> <u>of</u> <u>formation</u> is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

<u>Standard</u> <u>Enthalpy</u> <u>Change</u> is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}

For the reaction

   2NH₃   +      3N₂O   →      4N₂    +     3H₂O

2(-46.2)   +     3(82.05)      4(0)    +    3(-241.8)

\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]

\Delta H^{0}=-725.4-153.75

\Delta H^{0}=-879.15

<u>The standard enthalpy change for the reaction is </u>\Delta H^{0}=-879.15<u> kJ</u>

8 0
2 years ago
Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a
svetoff [14.1K]

Answer:

See Explanation

Explanation:

For SF6;

Since;

1.25 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55

For SF4;

Since;

1.88 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/ 1.88  = 2.36

Hence;

Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4

=

3.55/2.36 = 1.5

Hence the law of multiple proportion is obeyed here.

3 0
3 years ago
A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) &lt;---&gt; N2(g) 3H2(g) At equilibrium, it was fou
Softa [21]

Answer:

Kc for this equilibrium is 2.30*10⁻⁶

Explanation:

Equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction and the concentrations of reactants and products are held constant.

Being:

aA + bB ⇔ cC + dD

the equilibrium constant Kc is defined as:

Kc=\frac{[C]^{c}*[D]^{d}  }{[A]^{a} *[B]^{b} }

In other words, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients. Kc is constant for a given temperature, that is to say that as the reaction temperature varies, its value varies.

In this case, being:

2 NH₃(g) ⇔ N₂(g) + 3 H₂(g)

the equilibrium constant Kc is:

Kc=\frac{[N_{2} ]*[H_{2} ]^{3}  }{[NH_{3} ]^{2} }

Being:

  • [N₂]= 0.0551 M
  • [H₂]= 0.0183 M
  • [NH₃]= 0.383 M

and replacing:

Kc=\frac{0.0551*0.0183^{3}  }{0.383^{2} }

you get:

Kc= 2.30*10⁻⁶

<u><em>Kc for this equilibrium is 2.30*10⁻⁶</em></u>

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Maybe to not get rained on.

Hahhahahaha I ain't sure tho

6 0
2 years ago
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Bond [772]
Hi , if you are asking for the types of energy , here's your answer:

1. Radiative energy , because the microwave is releasing radiation.
2.Light energy , because there is light inside the microwave.
3.electronic energy , because the microwave is using electricity.
8 0
3 years ago
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