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nevsk [136]
2 years ago
11

8.5ml of a sample of sea water solution was added to a 44.317g evaporating dish the combination weighted 52.987g after evaporati

ng the dish and content weighed 44.599g
Chemistry
1 answer:
Ratling [72]2 years ago
5 0

Answer:  There is no question, but we can calculate a couple of items:

Density of sea water sample = (52.987g-44.317g)/8.5ml

Inorganic content of sample (mostly salts) = (44.599g-44.317g)/(52.987g-44.317g) x 100% = percent inorganics in water sample

Explanation:

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AURORKA [14]

3H_{2}+N_{2}⇔2NH_{3}

Decreasing the temperature of the reaction,the reaction shifts forward.

The explanation is given below.

Explanation:

If the temperature of the reaction mixture is increased,then the equilibrium will shift to decrease the temperature.

If the temperature of the reaction mixture is decreased,then the equilibrium will shift to increase the temperature.

During the formation of the ammonia,it gives off heat.So it is an exothermic reaction.

3H_{2}+N_{2}⇔2NH_{3}

A decrease in the temperature favors the reaction that is exothermic (the forward reaction)because it produces energy.Therefore,if the temperature is decreased,the yield of the ammonia increases.

<em>Therefore if the temperature is increased,the reaction shifts forward and the yield of the ammonia increases and it is an exothermic reaction.</em>

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3 years ago
What is the isotope notation of the element that has an atomic number of 24 and a mass number of 52?
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Chromium

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2 years ago
What two properties most affect the strength of the gravitational forces
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1) Masses of the object

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An evacuated 276 mL glass bulb weighs 129.6375 g. Filled with an unknown gas, the bulb weighs 130.0318 g. Calculate the gas dens
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density=1.43 g/L

Explanation:

Since the density formula is density = mass / volume, we need to find out the mass of the gas and the volume is that of the container.

The mass of the gas is  130.0318 g-129.6375 g=0.3943 g

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2 years ago
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. Wha
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We have that the molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

Generally the equation for the Rouault's law is mathematically given as

P=P_0 N

22.67=23.8*\frac{\frac{12.5}{18}}{\frac{125}{18}+\frac{15}{m}}\\\\\6.95+\frac{15}{m}=7.29\\\\\frac{15}{m}=7.29-6.95\\\\m=\frac{15}{0.34}\\\\m=44.11g/mol

Therefore

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