Answer:
Throughout the explanation section, the reason behind the given statement is described.
Explanation:
- The chemicals thus produced were indeed opposite or separate from the reaction mixture, this same reaction wouldn’t change when it's more balanced than some of the reactants.
- Another reason is that the development of advanced organisms, as well as chemical alterations, is irreversible throughout nature cant undo the chemical modifications.
The the last one, but isn't it c6h12o6?
Explanation:
Given parameters:
Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole
Unknown:
Mass of the sulfur trioxide = ?
Solution:
To solve for the mass of the sample of sulfur trioxide:
- Find the molar mass of the compound i.e SO₃
atomic mass of S = 32g
O = 16g
molar mass = 32 + 3(16) = 80g/mol
mass of SO₃ = number of moles x molar mass
mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg
Learn more:
mole calculation brainly.com/question/13064292
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Given mass of Scandium = 50.0 g
Increase in temperature of the metal when heated = 
Heat absorbed by Scandium = 
The equation showing the relationship between heat, mass, specific heat and temperature change:

Where Q is heat = 
m is mass = 50.0 g
ΔT = 
On plugging in the values and solving for C(specific heat) we get,
=50.0g(C)(
)
C = 0.491
Specific heat of the metal = 0.491