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Vikki [24]
3 years ago
15

How did you get the 3.2?

Chemistry
1 answer:
Helga [31]3 years ago
8 0
I don't understand what you mean??

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What temperature change in Celsius degrees is produced when 800. J is absorbed by 100. G of water?
g100num [7]

Answer: The final temperature is equal to

45 Celsius

Explanation:

Explanation:

We have the amount of energy gain

Q

=

m

⋅

c

⋅

Δ

T

=

m

c

Δ

t

where

c

=

4.184

J

/

g

.

C

is the specific heat of water,

m

is the mass of water

⇒

840

=

10

x

4.184

⋅

(

t

−

25

)

t

=

840

10

x

4.184

+

25

=

45

i.e.

45

∘

C

6 0
4 years ago
What effect does a lone electron pair have on molecular shape?
loris [4]

Using the VSPER theory, the effect of lone pairs on molecular shape can be discussed.

There are 3 types of electron pairs present in a molecular shape: bond pair -bond pair, lone pair - bond pair, lone pair - lone pair.

Strength of repulsions between these three types of pair follows the order:

lone pair- lone pair > lone pair - bond pair > bond pair - bond pair

Whenever there is an addition of lone pairs to the geometry, some distortions take place which decreases the bond angles and some asymmetry is attained in the original molecular shape.

4 0
3 years ago
Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen
PSYCHO15rus [73]
Assuming we have 100g, this means that

39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get

1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

Empirical formula is CH4N

<span>The mass of the empirical formula is
12 + 4 + 14 = 30

Since the molar mass is double, we multiply all our subscripts

The molecular formula is C2H8N2

The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
5 0
3 years ago
In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
4 years ago
PLEASE HELP, DUE AT 12:00
elena55 [62]

Answer:

<h2>5.C</h2><h2>6.D</h2>

Explanation:

YONG ISA PO ETO HINDI KO PO ALAM TOH

7 0
3 years ago
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