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Leno4ka [110]
3 years ago
15

Find the error makayla said that 3/4 of figure 1>2/4 find and correct her mistake

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0
Makayla forgot to include figure 1.
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2 years ago
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The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original
evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

{:\implies \quad \sf 5(s+8)=65}

{:\implies \quad \sf 5s+5\times 8=65}

{:\implies \quad \sf 5s+40=65}

{:\implies \quad \sf 5s=65-40}

{:\implies \quad \sf 5s=25}

{:\implies \quad \sf s=\dfrac{25}{5}=5}

{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

8 0
2 years ago
URGENT NEED HELP FAST LINKS WILL BE REPORTED
dolphi86 [110]

Answer:

model B is shaded to represent 37.5%

here,

=3÷8×100%

=37.5%

7 0
2 years ago
Select the correct answer.
Setler79 [48]

Answer:

A. 2·x² + 16·x + 32 ≥ 254

Step-by-step explanation:

The given dimensional relationship between the dimensions of the photo in the center of the cake and the dimensions of the cake are

The width of the cake = The width of the photo at the center of the cake, x + 4 inches

The length of the cake = 2 × The width of the cake

The area of the cake Wanda is working on ≥ 254 in.²

Where 'x' represents the width of the photo (at the center of the cake), let 'W' represent the width of the cake, let 'L' represent the length of the cake, we get;

W = x + 4

L = 2 × W

Area of the cake, A = W × L ≥ 254

∴ A = (x + 4) × 2 × (x + 4) = 2·x² + 16·x + 32 ≥ 254

The inequality representing the solution is therefore;

2·x² + 16·x + 32 ≥ 254

3 0
3 years ago
Please help with this question
stealth61 [152]

Answer:

hi Step-by-step explanation:April 12, 1861: Battle of Fort Sumter. ...

June 30, 1861: Battle of Philippi. ...

July 21, 1861: First Battle of Bull Run/First Battle of Manassas. ...

August 28-29, 1861: Battle of Hatteras Inlet Batteries. ...

October 21, 1861: Battle of Ball's Bluff. ...

November 7, 1861: Battle of Belmont. ...

January 19, 1862: Battle of Mill Springs.

6 0
3 years ago
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